Answer:
The number is 1/4
___________________
Step-by-step explanation:
Look at the photo below for the details.
:)
Answer:
29.5 square inches
Step-by-step explanation:
Let's divide the shape into 3 parts to make it easy for us to find the area.
- a wide triangle
- a triangle
- a shorter rectangle
For the wider rectangle, the area is;
A1 = 8 × 2 = 16 in²
For the triangle, the area is;
A2 = ½(7 - 2) × 3
A2 = 7.5 in²
For the shorter rectangle, the area is;
A3 = 3 × 2
A3 = 6 in²
Total area = A1 + A2 + A3 = 16 + 7.5 + 6 = 29.5 square inches
Answer:
<em>LCM</em> = ![8y^{4}(y+ 10)^{2}(y + 8)](https://tex.z-dn.net/?f=8y%5E%7B4%7D%28y%2B%2010%29%5E%7B2%7D%28y%20%2B%208%29)
Step-by-step explanation:
Making factors of ![8y^{6}+ 144y^{5}+ 640y^{4}](https://tex.z-dn.net/?f=8y%5E%7B6%7D%2B%20144y%5E%7B5%7D%2B%20640y%5E%7B4%7D)
Taking
common:
![\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)](https://tex.z-dn.net/?f=%5CRightarrow%208y%5E%7B4%7D%20%28y%5E%7B2%7D%2B%2018y%2B%2080%29)
Using <em>factorization</em> method:
![\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)](https://tex.z-dn.net/?f=%5CRightarrow%208y%5E%7B4%7D%20%28y%5E%7B2%7D%2B%2010y%20%2B%208y%20%2B%2080%29%5C%5C%5CRightarrow%208y%5E%7B4%7D%20%28y%20%28y%2B%2010%29%20%2B%208%28y%20%2B%2010%29%29%5C%5C%5CRightarrow%208y%5E%7B4%7D%20%28y%2B%2010%29%28y%20%2B%208%29%29%5C%5C%5CRightarrow%20%5Cunderline%7B2y%5E%7B2%7D%7D%20%5Ctimes%20%204y%5E%7B2%7D%20%5Cunderline%7B%28y%2B%2010%29%7D%28y%20%2B%208%29%29%20.....%20%281%29)
Now, Making factors of ![2y^{4} + 40y^{3} + 200y^{2}](https://tex.z-dn.net/?f=2y%5E%7B4%7D%20%2B%2040y%5E%7B3%7D%20%2B%20200y%5E%7B2%7D)
Taking
common:
![\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)](https://tex.z-dn.net/?f=%5CRightarrow%202y%5E%7B2%7D%20%28y%5E%7B2%7D%2B%2020y%2B%20100%29)
Using <em>factorization</em> method:
![\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)](https://tex.z-dn.net/?f=%5CRightarrow%202y%5E%7B2%7D%20%28y%5E%7B2%7D%2B%2010y%2B%2010y%2B%20100%29%5C%5C%5CRightarrow%202y%5E%7B2%7D%20%28y%20%28y%2B%2010%29%20%2B%2010%28y%20%2B%2010%29%29%5C%5C%5CRightarrow%20%5Cunderline%20%7B2y%5E%7B2%7D%20%28y%2B%2010%29%7D%28y%20%2B%2010%29%20%20%20%20%20%20%20%20............%20%282%29)
The underlined parts show the Highest Common Factor(HCF).
i.e. <em>HCF</em> is
.
We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:
![HCF \times LCM = p \times q](https://tex.z-dn.net/?f=HCF%20%5Ctimes%20LCM%20%3D%20p%20%5Ctimes%20q)
Using equations <em>(1)</em> and <em>(2)</em>:
![\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)](https://tex.z-dn.net/?f=%5CRightarrow%202y%5E%7B2%7D%20%28y%2B%2010%29%20%5Ctimes%20LCM%20%3D%202y%5E%7B2%7D%20%5Ctimes%20%204y%5E%7B2%7D%28y%2B%2010%29%28y%20%2B%208%29%20%5Ctimes%202y%5E%7B2%7D%20%28y%2B%2010%29%28y%20%2B%2010%29%5C%5C%5CRightarrow%20LCM%20%3D%202y%5E%7B2%7D%20%5Ctimes%20%204y%5E%7B2%7D%28y%2B%2010%29%28y%20%2B%208%29%20%5Ctimes%20%28y%20%2B%2010%29%5C%5C%5CRightarrow%20LCM%20%3D%208y%5E%7B4%7D%28y%2B%2010%29%5E%7B2%7D%28y%20%2B%208%29)
Hence, <em>LCM</em> = ![8y^{4}(y+ 10)^{2}(y + 8)](https://tex.z-dn.net/?f=8y%5E%7B4%7D%28y%2B%2010%29%5E%7B2%7D%28y%20%2B%208%29)
<u>5 hours</u><u> long would it take the </u><u>faster </u><u>maid cleaning alone.</u>
What is a linear equation in math?
- A linear equation only has one or two variables.
- No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction.
- When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.
Suppose, time taken by faster maid be x , hours.
So, time taken by slower maid ,
( 4 time faster maid )
Now, time taken by both of the made together is given by ,
![( \frac{x_{1}x_{2} }{x_{1} + x_{2} } )](https://tex.z-dn.net/?f=%28%20%5Cfrac%7Bx_%7B1%7Dx_%7B2%7D%20%20%7D%7Bx_%7B1%7D%20%2B%20x_%7B2%7D%20%7D%20%29)
![\frac{x_{1}(4x_{1} ) }{x_{1} + 4x_{1} } = 4 hours](https://tex.z-dn.net/?f=%5Cfrac%7Bx_%7B1%7D%284x_%7B1%7D%20%29%20%7D%7Bx_%7B1%7D%20%2B%204x_%7B1%7D%20%7D%20%20%3D%204%20hours)
![\frac{4x_{1} }{5} = 4 hours](https://tex.z-dn.net/?f=%5Cfrac%7B4x_%7B1%7D%20%7D%7B5%7D%20%20%3D%204%20hours)
which is the time required by faster maid.
Learn more about linear equation
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