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2 years ago

14

What is the volume of this prism?

1 answer:

marin [14]2 years ago

7 0

Answer:

160 u^3

Step-by-step explanation:

For the sake of ease, I will split this prism into 2 prisms. One prism will be 2x4x5 while the second one will be 4x5x6. The volume of the prism will be the sum of the volume of both prisms.

Prism A: Volume would be lwh or 2*4*5=40

Prism B: Volume would also be lwh which is 4*5*6=120

40+120=160

The volume is 160 units^3

Hope this is correct and helps!

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Find the values of which satisfy the equation. 2 cos (2B+30°) = -√3 in the domain OP ≤B≤360°

PSYCHO15rus [73]

Answer:

60 and 90

Step-by-step explanation:

$2 \cos(2 \beta + 30) = - \sqrt{3}$

$\cos(2 \beta + 30) = - \frac{ \sqrt{3} }{2}$

$2 \beta + 30 = \cos {}^{ - 1} ( \frac{ - \sqrt{3} }{2} )$

First solution.

$2 \beta + 30 = 150$

$2 \beta = 120$

$\beta = 60$

Second solution

$2 \beta + 30 = 210$

$2 \beta = 180$

$\beta = 90$

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1 year ago

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3 years ago

The length of a room is 20 feet and its width is 12 feet. Whats the perimeter

Tems11 [23]

Perimeter = 2 x Length + 2 x Width

Perimeter = 2(20) + 2(12) = 64 feet.

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Answer: Perimeter = 64 feet.
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3 years ago

Read 2 more answers

Find the exponential function P(t)=P0a^t where P(2)=5 and P(4)=10

asambeis [7]

Answer:

$P(t)=\frac{5}{2} \cdot (\sqrt{2})^t$

Step-by-step explanation:

$P(2)=5$ meants when $t=2$ , that the value for $P(t)$ is 5.

So this gives us this equation:

$5=P_0 \cdot a^2$

$P(4)=10$ meants when $t=4$ , that the value for $P(t)$ is 10.

So this gives us this equation:

$10=P_0 \cdot a^4$

So I take equation 2 and divide it be equation 1 I get:

$\frac{10}{5}=\frac{P_0 \cdot a_4}{P_0 \cdot a_2}$

Simplifying:

$2=a^2$

Since the base for an exponential function can't be negative then $a=\sqrt{2}$ .

So plugging into one of my equations I began with gives me an equation to solve for the initial value, $P_0$ :

$5=P_0 \cdot (\sqrt{2})^2$

$5=P_0 \cdot 2$

Divide both sides by 2:

$\frac{5}{2}=P_0$

The function is:

$P(t)=\frac{5}{2} \cdot (\sqrt{2})^t$

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3 years ago

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WARRIOR [948]

1. 2
2. 1
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I'll post the rest in the comments

3 0

3 years ago