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3 years ago

A sphere has a height of 26. Find the surface area, volume and density (D=m/v , where m is 72)

Mathematics

1 answer:

dexar [7]3 years ago

3 0

Answer:

Surface Area: 2123.72

Volume: 9202.77

Density: 0.0078

Step-by-step explanation:

For a sphere, the height is the diameter.

Also we know the radius is half of the diameter.

<em>Since height is 26, diameter is 26 as well. Thus, </em><em>radius </em><em>is half of 26, which is </em><em>13</em><em>.</em>

<em />

<u>Formulas:</u>

Surface area of sphere = 4πr^2

Volume of sphere = $\frac{4}{3}\pi r^3$

Density = mass/volume

Firstly, the surface area:

$4\pi r^2\\=4\pi (13)^2\\=2123.72$

Next, the volume:

$\frac{4}{3}\pi r^3\\=\frac{4}{3}\pi (13)^3\\\\=9202.77$

Lastly, density:

$\frac{Mass}{Volume}\\=\frac{72}{9202.77}\\=0.0078$

*<u>Note:</u> all answers are given as is since no units were given

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<h2> Question # 1</h2>

Part A) Is the relation a function? Explain.

A function relates each element of a set with exactly one element of another set.

Important things for a relationship to be a function:

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A function cannot have one-to-many relationship.

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relates each element of a set with exactly one element of another set

is single-valued, means It is not giving back 2 or more results for the same input. In other words, it is not having one-to-many relation.

It is in fact, having many to one. For example, the pairs (0, 2) and (-4, 2) is having many- to-one relationship.

So, from the above observation, it is clear that the relationship is a function.

Part B) What is the domain of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

Also we know that domain of the relation is the set of all the x-values of an ordered pairs.

So, the domain of the relation: {-4, -3, -2, 0, 2, 3}

Part C) What is the range of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

As we know that the range of a relationship is the set of all the y-values of an ordered pair.

So, the range of the relationship will be: { -3, -1, 0, 2, 3}

<em>Note:</em>

The duplicated entries in the domain and range are written only once.
Also, the domain and range can be written in ascending order.

Part D) What is the value of y when x = 2? Explain

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

From the given points on the coordinate plane, it is clear that when the value of x = 2, then the value of y = -3

Therefore, the value of y is -2 when x = 2

<h2> Question # 2</h2>

Considering the points on coordinate plane

(-4, -1), (-2, 1), (0, -3), (2, 3), (4, -2)

If we bring a point, let say (2, 4), and graphed on the coordinate system, then the relation will no longer be function.

The reason is that the induction of the point (2, 4) would violate the definition of a relation to be a function.

Observe that (2, 4) and (2, 3) will make the relation having one-to-many relationship as (2, 4) and (2, 3) is giving 2 outputs i.e. y = 4, and y = 3 for a single input i.e. x = 2.

Therefore, the induction of the point (2, 4), when graphed, makes the relation not a function.

<h2> Question # 3</h2>

Part A)

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ ; $x = -5$

The attached figure a shows the graph for the function

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

In the attached figure a, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -5

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

$|\left-5\right\:-\:3|\:-\:2....[A]$

Solving

$\left|-5-3\right|$

$\mathrm{Subtract\:the\:numbers:}\:-5-3=-8$

$=\left|-8\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a$

$\left|-8\right|=8$

So,

$\left|-5-3\right|=8$

Equation [A] becomes

$\:|-5\:-\:3|\:-\:2\:=8\:-\:2\:$ ∵ $\left|-5-3\right|=8$

$=6$

Therefore,

the value of $f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ at $x = -5$ will be 6.

i.e. $f(x)=6$

<h2 />

Part B)

$g\left(x\right)=1.5x;\:x=0.2$

The attached figure b shows the graph for the function

$g\left(x\right)=1.5x$

In the attached figure b, the graph shows that the function represents a linear relationship as the graph is a straight line.

Evaluate the function for x = 0.2

$g\left(x\right)=1.5x$

Putting x = 0.2

$g\left(x\right)=1.5\left(0.2\right)$

$1.5\left(0.2\right)=0.3$

$g\left(x\right)=0.3$

So,

the value of $g\left(x\right)=1.5x$ at $x = 0.2$ will be 0.3.

i.e. $g\left(x\right)=0.3$

Part C)

$p\left(x\right)\:=\:|7\:-\:2x|;\:x\:=\:-3$

As the absolute value of a number will be never negative.

The attached figure c shows the graph for the function

$p\left(x\right)\:=\:|7\:-\:2x|$

In the attached figure c, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -3

$p\left(x\right)\:=\:|7\:-\:2x|$

Solving

$\left|7-2x\right|$

$\left|7-2\left(-3\right)\right|$

$=\left|7+6\right|$

$=\left|13\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$=13$

So,

$\left|7-2x\right|=13$

So,

the value of $p\left(x\right)\:=\:|7\:-\:2x|$ at $x = -3$ will be 13.

i.e $p\left(x\right)\:=13$

Keywords: function, relation

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4 years ago