Answer:
The function is decreasing for all real values of x where x < 1.5.
Step-by-step explanation:
we have
This is a vertical parabola open upward
The vertex is a minimum
The vertex is the point (1.5,-6.25)
we know that
The function is decreasing in the interval ----> (-∞,1.5) x < 1.5
That means----> the function is decreasing for all real values of x less than 1.5
The function is increasing in the interval ----> (1.5,∞) x> 1.5
That means----> the function is increasing for all real values of x greater than 1.5
see the attached figure to better understand the problem
therefore
The statement that is true is
The function is decreasing for all real values of x where x < 1.5.
Answer:
-1.33 and so on
Step-by-step explanation:
Take each fraction and plug it into a calculator. 2/3 is really 2 divide by 3. Same with the 5 and 6. You should get 0.67 and so on for 2/3 and 0.83 and so on for the 5/6. Subtract as shown in the problem. You should get 0.67-0.83= -0.1666 so on. Multiply by 8 to get -1.33 and so on. The "and so on" means this decimal is repeating. Hope this Helps!
ABD is the right triangle. AD is the hypotenuse.
By the <span>Pythagorean theorem:
</span>
<span>
s = 17 units.</span>
Answer:
Step-by-step explanation:
Answer:
There are 1% probability that the last person gets to sit in their assigned seat
Step-by-step explanation:
The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.
If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.
LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!
Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.
P = 99!/100! = 99!/ (100 * 99!) = 1/100
There are 1% probability that the last person gets to sit in their assigned seat
