AD || BC
<span>• AB = CD </span>
<span>• ∠BAD = ∠CDA (a given condition ∵ ABCD is an isosceles trapezium) </span>
<span>The diagonals AC and BD create two ∆'s: ∆ABD, and ∆ACD </span>
<span>The two ∆'s are congruent (SAS). </span>
<span>(S): AB = CD </span>
<span>(A): ∠BAD = ∠CDA
</span><span>(S): AD = DA (common side) </span>
<span>
The corresponding sides of the two ∆'s, BD and AC, are also congruent. </span>
<span>(the two diagonals of the trapezium/trapezoid)
</span>
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Answer:
210 mph
Step-by-step explanation:
speed of jet = x
headwind: speed = x - 27
time taken = 1134.6/(x - 27)
tailwind: speed = x + 27
time taken = 1469.4/(x + 27)
same amount of time:
1134.6/(x - 27) = 1469.4/(x + 27)
Cross multiply,
1134.6(x + 27) = 1469.4(x - 27)
1134.6x + 30634.2 = 1469.4x - 39673.8
334.8x = 70308
x = 210 mph
Make the fractions into common denominators
turn 1/2 into 2/4 (common denominator of 4 with 1/4)
then add them
8+7 is 15
1/4+2/4 is 3/4
15+3/4 is 15 3/4
