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Zielflug [23.3K]
3 years ago
10

The circumference of a circle is 18 π π m. Find its diameter, in meters

Mathematics
2 answers:
Zinaida [17]3 years ago
6 0

Answer:

18 meters

Step-by-step explanation:

The circumference is given by

C = pi *d

18 pi = pi *d

Divide each side by pi

18 pi / pi = pi * d/pi

18 =d

andriy [413]3 years ago
6 0

Answer:

18 m

Step-by-step explanation:

C = π · d

18π = π · d

18 = d

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Please help and explain.
Radda [10]

Explanation:

Vertex form of a quadratic function is given by y = a(x - h)² + k

where

1) 'a' determines if parabola is stretched or compressed.

   If a > 1 then graph is stretched by a factor of a.

   If 0 < a < 1, then graph is compressed by a factor of a.

2) If a > 0 then graph opens upwards with a happy face. (minimum)

3) If a < 0 then graph opens downwards with a sad face. (maximum)

4) (h, k) is the vertex point

5) The axis of symmetry is x = h

While solving for y = 1(x - 4)² + 3

Identify following's:

Vertex: (h, k) = (4, 3)

Axis of symmetry: x = 4

Max/Min: As here a > 0, Minimum (4, 3)

Stretch/compression: a = 1, the graph is stretched by a factor of 1.

Direction of opening: As a > 0, the graph opens upwards.

7 0
2 years ago
Linda. owed 8 lawns this week and earned $56. how much would Linda have earned if she had mowed 10 lawns?
Drupady [299]
56 / 8 = 7
7 * 10 = 70

She would have earned $70

6 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
Someone please help me with this question
Sauron [17]

Answer:

3

Step-by-step explanation:

Again, anything to the 0th power is equal to 1.

The 0th power is attached to the b, so this means that b = 1. Multiply 9 and (1) together to get 9.

Now you can subtract 9 from 12 to get 3 as your final answer.

5 0
3 years ago
Read 2 more answers
What is the surface area of the sphere below?
tatiyna

Hey there! I'm happy to help!

To find the surface area of a sphere, here is what you do.

You square the radius.

4²=16

You multiply by 4.

16×4=64

And you multiply by pi!

64×π=64π

Therefore, the surface area of the sphere is A. 64π units². It's that easy!

Now you can find the surface area of a sphere! Have a wonderful day! :D

3 0
3 years ago
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