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german
3 years ago
10

I need help with this please!

Mathematics
2 answers:
babunello [35]3 years ago
4 0

Answer:

a!

Step-by-step explanation:

It's 3^6 because the negatives cancel out

faltersainse [42]3 years ago
4 0

Answer:

It equals 729.

Step-by-step explanation:

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!!Determine if the figure has line, points, and/or rotational symmetry.!!
pshichka [43]

Answer:

line

Step-by-step explanation:

you can obviously see lines in the shape

4 0
3 years ago
I need to get aleks done on june 30th
Kazeer [188]
Pretty much saying 5+ (x*10)_<-25
3 0
3 years ago
Read 2 more answers
Please help asap!!! i dont understand it
pshichka [43]

Answer:

a

Step-by-step explanation:

A perpendicular bisector, intersects a line at its mid point and is perpendicular to it.

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13)

m = \frac{13-1}{9-(-7)} = \frac{12}{9+7} = \frac{12}{16} = \frac{3}{4}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{3}{4} } = - \frac{4}{3} ←  slope of perpendicular bisector

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(\frac{x_{1}+x_{2}  }{2}, \frac{y_{1}+y_{2}  }{2} )

using (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13) , then

midpoint = ( \frac{-7+9}{2}, \frac{1+13}{2} ) = ( \frac{2}{2}, \frac{14}{2} ) = (1, 7 )

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{4}{3} , then

y = - \frac{4}{3} x + c ← is the partial equation

To find c substitute the midpoint (1, 7) into the partial equation

7 = - \frac{4}{3} + c ⇒ c = \frac{21}{3} + \frac{4}{3} = \frac{25}{3}

y = - \frac{4}{3} x + \frac{25}{3} ← equation of perpendicular bisector

7 0
3 years ago
the value of k so that the line Containing the points (-8,k) and (-4,-8) is perpendicular) to the line containing the points (10
In-s [12.5K]

Answer:

k= \frac{-34}{3}

Step-by-step explanation:

<u>Step 1 :</u>-

<u>Perpendicular condition :-</u>

<u>Step 1:-</u>

Two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

m_{2} = \frac{-1}{m_{1} }

m_{1} m_{2} = -1

<u>Step 2:-</u>

The given points are (-8,k) and (-4,-8)

m_{1} = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

finding slope of the first line is m_{1}

using formula m_{1} = \frac{-8-k}{-4+8}

=  \frac{-8-k}{4}

finding slope of the second line is m_{2}

using formula m_{2} = \frac{--5+11}{5-10}

=  \frac{6}{-5}

<u>Step 3:</u>-

using perpendicular condition

The two lines are perpendicular and their slopes are

m_{1} m_{2} = -1

(\frac{-k-8}{4} )(\frac{-6}{5} )= -1

simplification,we get solution is

\frac{6(k+8)}{20} =-1

6 k+48 =-20

6 k = -20 -48

6 k = -68

\frac{-68}{6}

k= \frac{-34}{3}

<u>Final answer is </u>

k= \frac{-34}{3}

8 0
3 years ago
From triangle PQR is P = 90°, PQ = 15.5 dm and PR = 11,7 dm. Calculate QR in dm. Round to one decimal.
Irina18 [472]

Answer:

QR = 19.4

Step-by-step explanation:

Use Pythagoras because p = 90°

Qr is hypotenuse

; (15.5)² + (11.7)²

= 377.14

√377.14

= 19.42009

= 19.42

= 19.4

hope it helps ☺️

4 0
3 years ago
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