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Bond [772]
3 years ago
12

From triangle PQR is P = 90°, PQ = 15.5 dm and PR = 11,7 dm. Calculate QR in dm. Round to one decimal.

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0

Answer:

QR = 19.4

Step-by-step explanation:

Use Pythagoras because p = 90°

Qr is hypotenuse

; (15.5)² + (11.7)²

= 377.14

√377.14

= 19.42009

= 19.42

= 19.4

hope it helps ☺️

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andreyandreev [35.5K]

Answer:

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There are two best ways to solve this.

using cosine method:

cos(n) =  \frac{adjacent}{hypotenuse}

cos(60) = \frac{adjacent}{6\sqrt{2} }

adjacent,n = cos(60) * 6\sqrt{2}

n  =                                    3\sqrt{2}

using sine method:

sin(n) = \frac{opposite}{hypotenuse}

sin(30)=  \frac{n}{6\sqrt{2} }

n  = sin(30) * 6\sqrt{2}

n = 3\sqrt{2}

There are many ways, not to make it complex, these are the best ways to solve for n. Hope it helps ~

5 0
2 years ago
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Anarel [89]

Answer:

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5 0
2 years ago
Two friends Ana and Juan are buying books by joining the History Book
Travka [436]

Answer:

Ana  spent $17  per book on average.

Juan  spent $14.78  per book on average.

y = $15 + 17x--------- equation 1

y= $10 + 14.78 x------------- equation 2

Step-by-step explanation:

Ana has to pay a yearly fee of $15 to join.

She spends a total of $525 for 30 books.

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Price per book on the average = $510/30= $ 17

Ana  spent $17  per book on average.

Juan has to pay a yearly fee of $10 to join.

He spends a total of $350 for 23 books.

The amount spent on books = Total amount - yearly fee

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Price per book on the average = $340/23= $ 14.78≅ $15

Juan  spent $14.78  per book on average.

The function can be established if y gives the total cost and x gives the number of books

y = $15 + 17x--------- equation 1

y= $10 + 14.78 x------------- equation 2

Juan has a better deal because the yearly fee is less also the price per book is less.

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3 years ago
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Juliette [100K]

Answer: 26/3

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So when dividing by a fraction, we can just multiply

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4 and 2 reduce to 2 and 1.

Multiplying across the numerator and denominators we have 26/3.

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Answer:

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