<span>(a.)
Let's say α is the angle that subtends from the top of the screen to horizontal eye-level.
Let β be the angle that subtends from the bottom of the screen to horizontal eye-level.
tanα = (22 + 10 - 4) / x = 28/x
α = arctan(28/x)
tanβ = (10 - 4) / x = 6/x
β = arctan(6/x)
Ɵ = α - β
Ɵ = arctan(28/x) - arctan(6/x)
(b.)
tanƟ = tan(α - β) = (tanα - tanβ) / (1 + tanα tanβ)
tanƟ = (28/x - 6/x) / [1 + (28/x)(6/x)]
tanƟ = (22/x) / [1 + (168/x²)]
tanƟ = 22x / (x² + 168)
Ɵ = arctan[22x / (x² + 168)]</span>
Answer:
yes what is the question
Step-by-step explanation:
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Answer:
so what should we do for it
Answer:
191
Step-by-step explanation:
955 = 5x
divide both sides by 5 to get x by itself
x = 191
I will do Point A carefully, The others I will indicate. Start with the Given Point A. Then do the translations
A(-1,2) Original Point
Reflection: about x axis:x stays the same; y becomes -y:Result(-1,-2)
T<-3,4>: x goes three left, y goes 4 up (-1 - 3, -2 + 4): Result(-4,2)
R90 CCW: Point (x,y) becomes (-y , x ) So (-4,2) becomes(-2, - 4): Result (-2, - 4)
B(4,2) Original Point
- Reflection: (4, - 2)
- T< (-3,4): (4-3,-2 + 4): (1 , 2)
- R90 CCW: (-y,x) = (-2 , 1)
C(4, -5) Original Point
- Reflection (4,5)
- T<-3,4): (4 - 3, 5 + 4): (1,9)
- R90, CCW (-9 , 1)
D(-1 , -5) Original Point
- Reflection (-1,5)
- T(<-3,4): (-1 - 3, 5 + 4): (-4,9)
- R90, CCW ( - 9, - 4)
Note: CCW means Counter Clockwise
The graph on the left is the same one you have been given.
The graph on the right is the same figure after all the transformations