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patriot [66]
3 years ago
6

Write an expression, using an exponent, that is equivalent to 9\times 9\times 9\times 9\times 9\times 9\times 99×9×9×9×9×9×9

Mathematics
2 answers:
jeka57 [31]3 years ago
7 0
Nine to the eighth power
Zigmanuir [339]3 years ago
7 0

9^88 would be the answer

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Nimfa-mama [501]

Answer:

7x - 12 = 3x - 2

Step-by-step explanation:

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2 years ago
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Solve this question<br>What is 511+85​
labwork [276]

Answer:596

Step-by-step explanation:

511+85​(5 is by itself),(8+1=9)(1+5=6)

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596

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7 0
4 years ago
Recorded here are the germination times (in days) for ten randomly chosen seeds of a new type of bean. See Attached Excel for Da
alexgriva [62]

Answer:

The 99% confidence interval for the mean germination time is (12.3, 19.3).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>Recorded here are the germination times (in days) for ten randomly  chosen seeds of a new type of bean: 18, 12, 20, 17, 14, 15, 13, 11, 21, 17. Assume that the population germination time is normally distributed. Find the 99% confidence interval for the mean germination time.</em>

<em />

We start calculating the sample mean M and standard deviation s:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{10}(18+12+20+17+14+15+13+11+21+17)\\\\\\M=\dfrac{158}{10}\\\\\\M=15.8\\\\\\

s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{9}((18-15.8)^2+(12-15.8)^2+(20-15.8)^2+. . . +(17-15.8)^2)}\\\\\\s=\sqrt{\dfrac{101.6}{9}}\\\\\\s=\sqrt{11.3}=3.4\\\\\\

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=15.8.

The sample size is N=10.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{3.4}{\sqrt{10}}=\dfrac{3.4}{3.162}=1.075

The degrees of freedom for this sample size are:

df=n-1=10-1=9

The t-value for a 99% confidence interval and 9 degrees of freedom is t=3.25.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=3.25 \cdot 1.075=3.49

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 15.8-3.49=12.3\\\\UL=M+t \cdot s_M = 15.8+3.49=19.3

The 99% confidence interval for the mean germination time is (12.3, 19.3).

8 0
3 years ago
What is the slope of the line shown?
koban [17]

Answer:

So buddy this is going to get a bad rating I know but I'm going to help you out as much as I can without seeing a picture so for linear equations the formula is y=mx+b anyways the slope is m and to find it, look at the line and see how many times it goes up till it lands on a correct point. once you have that you can see how many times it went up and over. Because your slope is your rise over run (rise/run) and so for example <em>if</em> it was c then it would be 3/3 meaning it goes up 3 and over 3. So to find the right one just find a starting point and see how much it goes over to the right. if it goes over to the left then its negative instead of run over to the right. And if it goes down instead of rise then its negative. Hope this helps you find your answer now and in the future.

5 0
4 years ago
The histogram shows the number of laps completed by swimmers on a team during practice.
Romashka [77]

Answer:

A) 10-14

B) 45

C) 6.7%

Step-by-step explanation:

A) The interval that contain the most values can be gotten by looking at the histogram and selecting the interval with the highest frequency. Hence the interval 10-14 contains the most values because it has a frequency of 20.

B)The total number of swimmers is gotten by summing all the frequency of each individual lap. Hence:

Total swimmers on team = 10 + 12 + 20 + 0 + 3 = 45 swimmers

C) The percentage of swimmers who swam more than 14 laps = (number of swimmers that swam more than 14 laps/total swimmers) * 100%

The percentage of swimmers who swam more than 14 laps = [(0 + 3)/45] * 100% = (3/45) * 100% = 6.7%

7 0
3 years ago
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