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Mrrafil [7]
3 years ago
8

Use the algebraic expression below to identify the following parts of the

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
6 0

Answer:

−4x+13

Step-by-step explanation:

collect like terms: (−3x−2x+x)+(16+5−8)

Snowcat [4.5K]3 years ago
5 0

Answer:

-3x-2x-x+16+5-8=-4x13

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It says solve for x and round to the nearest hundredth. <br> 1. 9 over 6 equals x over 10
emmainna [20.7K]

Answer:

1.110

Step-by-step explanation:

I hope that help's

5 0
3 years ago
Write a simplified polynomial expression in standard form to represent the area of the rectangle below. (2 points) A picture of
Jet001 [13]

Answer:

Area= 5x^2-18x -8

Step-by-step explanation:

If the rectangle show one side of length 5 x +2, and another side of length x - 4, then the area of this rectangle (given by the product of the sides' length) is:

Area = (5x+2)\,(x-4)\\Area = 5x^2-20x+2x-8\\Area= 5x^2-18x -8

which is already written in standard form.

4 0
3 years ago
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What's the square route of ten
Iteru [2.4K]
What's the square root of ten? 

√10 = ? 

√10 ≈ 3.16

The square root of 10 is about 3.16
6 0
3 years ago
Refer to the following distribution of commissions:______. Monthly Commissions Class Frequencies $600 up to $800 3 $800 up to 1,
blsea [12.9K]

Answer:

 the midpoint of the class with the greatest frequency 1500

Step-by-step explanation:

The illustration of the dataset given can be well represented in a table format as shown below.

Class                      Frequency                     Relative Frequency

$600 - $800                   3                              \mathbf{   \dfrac{3}{120} = 0.025}

$800 - $1000                  7                              \mathbf{   \dfrac{7}{120} = 0.059}

$1000 - $1200                11                              \mathbf{   \dfrac{11}{120} = 0.092}

$1200 - $1400                22                             \mathbf{   \dfrac{22}{120} = 0.183}

$1400 - $1600                40                            \mathbf{   \dfrac{40}{120} = 0.333}

$1600 - $1800                 24                            \mathbf{   \dfrac{24}{120} = 0.2}

$1800 - $2000                 9                            \mathbf{   \dfrac{9}{120} = 0.075}

$2000 - $2200                4                             \mathbf{   \dfrac{4}{120} = 0.033}

Total                               120                                           1

Therefore, the midpoint of the class with the greatest frequency is between  $1400 - $1600  since the frequency 40 happens to be the greatest frequency

The midpoint =\dfrac{upper \ limit + \ lower \ limit}{2}

The midpoint =\dfrac{1400+1600}{2}

= 1500

3 0
3 years ago
Find what is x in the following problem:<br><br> 15–(7+3x)=16–(4x–1)
monitta

I think x=9 hopefully I helped

6 0
3 years ago
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