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Kobotan [32]
2 years ago
15

Write a rule for the translation of ABC to A' B' C'

Mathematics
1 answer:
Anvisha [2.4K]2 years ago
5 0

Answer:

(x-2,y-4)

Step-by-step explanation:

Here, we want to calculate the rule for the translation

From the question, we can see that the new image was just formed as a movement of the old image by some particular units

The x-axis was move sideways while the y-axis was moved further down

The number of units is thus;

Y from 12 to 8

A movement of -4

For the x-axis

we have a movement of two units toward the left

So the rule is;

(x,y) to (x-2, y-4)

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Step-by-step explanation:

This the equation being simplified

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Step-by-step explanation:

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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
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Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

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