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Blizzard [7]
3 years ago
13

Use the distance formula to find the distance between each pair of points.u (2,3),v(5,7).

Mathematics
1 answer:
Elden [556K]3 years ago
5 0
(2,3), \ \ \ \ (5,7)\\\\Distance \ Formula:\ Given \ the \ two \ points \ (x _{1}, y _{1}) and (x _{2}, y _{2}), \\ \\the \ distance \ between \ these \ points \ is \ given \ by \ the \ formula: \\ \\ d= \sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2} \\\\d= \sqrt{( 5-2)^2 +( 7-3)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5


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A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
3 years ago
y = –6x 2 –12x – 2y = –4 how many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution
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Y = -6x + 2 . . . . . . . . (1)
-12x - 2y = -4 . . . . . . (2)
Putting (1) into (2), we have
-12x - 2(-6x + 2) = -4
-12x + 12x - 4 = -4
-4 = -4

Therefore, the system has infinite number of solutions.
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