Answer:
0.0105
Step-by-step explanation:
given that 30% of all houses need a paint job. Also, 15% of all houses need both a paint job and a new roof. Further, 7% of all houses that need a new roof also need new windows.
If total houses are 100, then 30 require a paint along. 15 require both paint and new roof.
Out of 15 houses which require new roof 7% need new windows
i.e. no of houses which need new windows = 
If there are total 100 houses, 1.05 houses require a new window
So probability that a randomly selectede house needs a new window
= 0.0105
Answer:
x ≤ 12.83
(Any number under or equal to 12.8333...)
Step-by-step explanation:
154 ≥ 12x
12.833.... ≥ x
x ≤ 12.83
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
5. Plane P
6. Line segment DB
7. Line CE
11. Ray BE (with an arrow on top from left to right) and Ray EC (with an arrow on top from left to right)
Answer:
(-2,1) (-3,0)
Step-by-step explanation:
It hits on the line
