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3 years ago

If x=3 substitute the value of x into the expression and simplify 3x+6

Mathematics

1 answer:

kotykmax [81]3 years ago

7 0

Answer:

Step-by-step explanation:

Plug in 3 as x:

3x + 6

3(3) + 6

9 + 6

= 15

So, the simplified expression if x = 3 is 15

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Solve A= 1/2bh for b. Then find the base of a triangle with a height of 6 inches and an area of 24 square inches.

lions [1.4K]

Answer:

The breadth of the triangle is 8 inches.

Step-by-step explanation:

Given that the area of the triangle is 24 sq inches and that the height is 6 inches

1/2 * b * 6 =24

b * 3= 24

b=8 inches

3 0

3 years ago

The sum of three numbers is 54. The third number is 2 times the second. The second number is 10 more than the first. What are th

Svetllana [295]

Answer:

8, 18 and 36 respectively.

<h2>explanation</h2>

sum=54

1st number=x

2nd number=x+10

3rd number =2(x+10)=2x+20

x+x+10+2x+20=54

put the liketerms together

x+x+2x=54-10-20

4x=24

divide both sides by 4 to get

x=8

Input the other values

6 0

3 years ago

Im stuck on this anyone know it?

bonufazy [111]

Answer:

The first one is correct

Step-by-step explanation:

8 0

2 years ago

A snack-size bag of M&Ms candies is opened. Inside, there are 12 red candies, 12 blue, 7 green, 13 brown, 3 orange, and 10 y

Anestetic [448]

Answer:

$\frac{1}{4180}$

Step-by-step explanation:

GIVEN: A snack-size bag of M&Ms candies is opened. Inside, there are $12$ red candies, $12$ blue, $7$ green, $13$ brown, $3$ orange, and $10$ yellow. Three candies are pulled from the bag in succession, without replacement.

TO FIND: What is the probability that the first two candies drawn are orange and the third is green.

SOLUTION:

Total candies in the bag $=57$

Probability that first ball is orange, $P(A)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{3}{57}=\frac{1}{19}$

Probability that second ball is orange, $P(B)=\frac{\text{total orange candies in bag}}{\text{total candies in bag}}$

$=\frac{2}{56}=\frac{1}{28}$

Probability that third ball is green, $P(C)=\frac{\text{total green candies in bag}}{\text{total candies in bag}}$

$=\frac{7}{55}$

Now, probability that first two balls are orange and third is green is

$=P(A)\times P(B)\times P(C)$

$=\frac{1}{19}\times\frac{1}{28}\times\frac{7}{55}$

$=\frac{1}{19}\times\frac{1}{4}\times\frac{1}{55}$

$=\frac{1}{4180}$

Hence, probability that first two balls are orange and third is green is $\frac{1}{4180}$

3 0

4 years ago

CAN SOMEONE HELP ME PLEASE

seropon [69]

Answer:

the answer is -4

Step-by-step explanation:

you take the points (0,6) and (4,-10), then you subtract -10 by 6 and you get -16. then you take 4 subtracted by 0 and you get 4. -16 divided by 4 is -4.

3 0

2 years ago