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3 years ago

What is 2,107,954 in expanded form

Mathematics

1 answer:

Simora [160]3 years ago

8 0

Answer:

2,000,000+100,000+7,000+ 900+50+4

Step-by-step explanation: Can i have brainliest?

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What is the answer 2(4y+1)=3y

SCORPION-xisa [38]

2(4y+1) = 3y. We need to solve for y.
First let's get ride of the parenthesis by developing 2(4y+1). This means to multiply 2 by 4y and 2 by 1, and add them.
2(4y+1) = 2*4y + 2*1 = 8y + 2
So 2(4y+1)=3y
8y+2 = 3y
Then you subtract 8y from each side to have the variables on a side and the numbers on the other:
3y - 8y = 8y + 2 - 8y
-5y = 2
Then you divide each side by -5 to get the variable y alone on a side and its value on the other:
(-5y)/-5 = 2/-5
y = -2/5

You can re-check your answer (very important):
2(4y + 1) = 2(4*-2/5 + 1) = -1.2
3y = 3 * -2/5 = -1.2
So 2(4y+1)=3y= -1.2
The answer has been approved.

Hope this Helps! :)

4 0

4 years ago

Is calculating his expenses from his work trip to San Francisco. Below is the expense log he kept while traveling.

Alika [10]

Answer:

Step-by-step explanation:

379.00 - 15.00 + 154.00 x 3 + 65.00 + 13.00 = 904

0.55 x 63 = 34.65

34.65 + 904 = 938.65

5 0

3 years ago

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Need a number line to show the answer to 1/10 ÷ 2

Taya2010 [7]

No you do not. I think I will help.

7 0

3 years ago

PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.

worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, $m\angleK=60^\circ$ , and $m\angle M= 45^\circ$

Refer the attached image.

In a triangle sum of three angles should be $180^\circ$ .

So,

$m\angle K+m\angle L+m\angle M=180^\circ$

Plugging the values of angle K and angle M, we get:

$60^\circ+m\angle L+45^\circ=180^\circ$

So,

$m\angle L=180^\circ-105^\circ=75^\circ$

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

$\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}$

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}$

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}$

We get the value of 'y'

$y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38$

So the length of the side KM is 13.38 units.

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}$

We get the value of 'x'

$x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79$

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM $= KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17$ units

6 0

3 years ago

Read 2 more answers

Someone please help I don’t understand!!!

Fantom [35]

Answer:

y=3

Step-by-step explanation:

This is because it is a straight line, there is no need for x-intercepts or y-intercepts because it already intercepts y at y=3.So, your answer is y=3

3 0

3 years ago