Janna buy 2bags of food for her dogs one bag weighs 37 pound the other bag weighs 15 pounds how many pounds do both bags weigh e
1 answer:
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Answer:
Step-by-step explanation:
There are a couple of equivalent expressions to the function . For example:
Factor:
If you add the terms inside the parentheses:
Basically you can add the like terms from the start and get the same result.
Therefore:
Answer:
The value of t test statistics is -2.25.
Step-by-step explanation:
We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 402 gram setting. It is believed that the machine is under filling the bags.
A 25 bag sample had a mean of 393 grams with a standard deviation of 20.
<u><em>Let </em></u><u><em> = mean filling of bags by the machine.</em></u>
So, Null Hypothesis, :
402 gram {means that the the machine is not under filling the bags}
Alternate Hypothesis, :
< 402 gram {means that the the machine is under filling the bags}
The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;
T.S. = ~
where, = sample mean bag filling = 393 grams
s = sample standard deviation = 20 grams
n = sample of bags = 25
So, <u><em>test statistics</em></u> = ~
= -2.25
The value of t test statistics is -2.25.
Answer:
(a) boxes of cat food had been sold.
(b) boxes of cat food had been sold.
Step-by-step explanation:
From the question,
Polly stacked the tins from five boxes of cat food onto an empty shelf and there were 15 tins of cat food in each box. That is,
5 × 15 tins of cat food were stacked onto the empty shelf.
5 × 15 = 75
Hence, 75 tins of cat food were stacked onto the empty shelf.
Also, from the question,
At the end of the week there were 20 tins left on the shelf and the rest of the tins had been sold, that is
75 - 20 tins had been sold
75 - 20 = 55
Hence, 55 tins of cat food had been sold.
To determine the number of boxes of cat food that had been sold,
Since there are 15 tins of cat food per box, then
we will divide 55 tins of cat food that had been sold by 15 tins of cat food per box
55 ÷ 15 =
Hence, boxes of cat food had been sold
(a) As a mixed number
Hence, boxes of cat food had been sold.
(b) As an improper fraction
Hence, boxes of cat food had been sold.