Answer: 0.00102%
Step-by-step explanation:
Given : Human body temperatures are normally distributed with a mean of
and a standard deviation of 
A hospital uses
as the lowest temperature considered to be a fever.
Let x be the random variable that represents the human body temperatures.

For x= 100.6, 
Using normal distribution table for z-values for right-tailed area ,
P(x>100.6)=
Hence, the required probability = 0.00102%
$56.25. Just take a calculator and write $12.50 times * 4.5 equals=.
<span>Question:
What percent of 200 is 0.5?
Solutions and discussions:
=> 200 is the 100% value of the numbers
=> 0.5 is the number in which we need to find the percentage value of it in
200.
How to solve. Simply follow the formula
=> 0.5 / 200 = 0.0025 – this is the to get the decimal value of the number
that we will be converting to percentage.
=> 0.0025 * 100% = 0.25%
Therefore 0.5 is 0.25% of 200.
</span>
Answer:
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Step-by-step explanation:
The options are missing; However, I'll simplify the given expression.
Given
![\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B32x%5E3y%5E6%7D%7D%7B%5Csqrt%5B3%5D%7B2x%5E9y%5E2%7D%20%7D)
Required
Write Equivalent Expression
To solve this expression, we'll make use of laws of indices throughout.
From laws of indices ![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
So,
gives

Also from laws of indices

So, the above expression can be further simplified to

Multiply the exponents gives

Substitute
for 32


From laws of indices

This law can be applied to the expression above;
becomes

Solve exponents


From laws of indices,
; So,
gives

The expression at the numerator can be combined to give

Lastly, From laws of indices,
; So,
becomes
![\frac{\sqrt[3]{(2y)}^{4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B%282y%29%7D%5E%7B4%7D%7D%7Bx%5E2%7D)
![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
Hence,
is equivalent to ![\frac{\sqrt[3]{16y^4}}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B16y%5E4%7D%7D%7Bx%5E2%7D)
36 take 150-40 then you would want to decide 3 from 110