Dan's car depreciates at a rate of 17% per year.
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Answer:
99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].
Step-by-step explanation:
We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.
Of the 250 employed individuals surveyed, 41 responded that they did work at home at least once per week.
Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;
P.Q. = ~ N(0,1)
where, = sample proportion of individuals who work at home at least once per week =
= 0.164
n = sample of individuals surveyed = 250
<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>
So, 99% confidence interval for the population proportion, p is ;
P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%
level of significance are -2.5758 & 2.5758}
P(-2.5758 < < 2.5758) = 0.99
P( <
<
) = 0.99
P( < p <
) = 0.99
<em>99% confidence interval for p</em> = [ ,
]
= [ ,
]
= [0.104 , 0.224]
Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].
Let's assume that the diagram or image that was not attached by you is similar to the image that I attached. The answer below may not be perfect but it is to give you an idea of what is expected of you in this circumstance.
Answer:
2.7 m
Step-by-step explanation:
Please kindly check the attached files for explanation.
