An ordered pair (x,y) is a solution to a system of equations if it makes all the equations true.
Let's check whether (–1, 5) makes the equations true.
Plugging –1 in the first equation for x and 5 in for y, we get
–1 + 5 = 4: TRUE
Plugging –1 in the second equation for x and 5 in for y, we get
–1 – 5 = –6: TRUE
Since it makes both the equations true, it's a solution to the system of equations. So the answer choice is D, the 4th one.
Answer:it would be 15 quarters and 10 dimes
Step-by-step explanation:
15 quarters is 3.75 and 10 dimes is $1, add them up you get $ 4.75
Step-by-step explanation:
x = number hours dog walking
y = number hours tutoring
x + y <= 11
6x + 10y >= 80
the solution is the common area below the first line and above the second line.
the first line is above the second line (due to the y-intercept of 11 vs. 8) until the crossing point.
for the crossing point we use the regular equations :
from the first we get
x = 11 - y
using this in the second
6×(11 - y) + 10y = 80
66 - 6y + 10y = 80
4y = 14
y = 14/4 = 7/2 = 3.5
x = 11 - y = 11 - 3.5 = 7.5
so, she has to do at least 3.5 hours tutoring (and then 7.5 hours dog walking) for the minimum of $80 earning, all the way up to the maximum of 11 hours tutoring (and 0 dog walking) for $110 earning.
6.25%=0.0625
P(t) = Initial Population * (1 + rate)^t
P(t) = 400,00*(1+0.0625)^t
P(t)= 400,00*(1+0.0625)^15
Pt=400
Answer:
14,16
Step-by-step explanation:
Let x be the first even number.
Let y be the 2nd even number.
Given, y - x = 2 (Since they are 2 consecutive even numbers.)
rearranging the equation: y = x+2 (equation 1)
Also given,
(equation 2)
Now we can substitute equation 1 into equation 2 to find x.
Given the smaller even number x, is 14, we will substitute x into equation1 to find y, the bigger even number.
y = 14+2
= 16
Therefore the 2 numbers are 14 and 16.
