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3 years ago

What the answer I don’t know it

Mathematics

2 answers:

viktelen [127]3 years ago

7 0

Answer:

Step-by-step explanation:

because negative minus negative is positive so its negative 6 plus 3

meriva3 years ago

5 0

The answer is B since a negative number being subtracted cancels out and becomes a number, for example: since its -(-3) it becomes positive.

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If you could help I would really appreciate it, but if not that’s fine. Thank you.

zloy xaker [14]

Answer:

2x - 5 if x ≤ 2

f(-1) = -7

Step-by-step explanation:

x ≤ 2 = (-1) ≤ 2

x > 2 = (-1) > 2

2x - 5

2(-1) - 5

-2 - 5

-7

8 0

2 years ago

I need help I don’t know how to do this

Law Incorporation [45]

Answer:

its about checkers cou nt and answer

Step-by-step explanation:

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3 years ago

ben has 6 pounds of bolts in his auto shop he has to seperate them into boxeseach with 1/3 pound of bolts how many boxes can he

IgorLugansk [536]

Answer:

2 pounds in each

Step-by-step explanation:

4 0

3 years ago

a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh

sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

$h=-16t^2+32t+48$

Let us assume that we need to find the time by it to reach the ground. It means h = 0

$-16t^2+32t+48=0$

The above is a quadratic equation. The value of t is given by :

$t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s$

So, it will take 2.11 seconds to reach the ground.

6 0

3 years ago

How would you test if an equation such as 4x-2y=11 is a function?

Ray Of Light [21]

Answer: By putting it on a graph

Step-by-step explanation:

5 0

3 years ago