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olchik [2.2K]
3 years ago
11

Una fuente circular tiene un diámetro de 80 pulgadas conciderando que una pulgada equivale a 2.54cm cual es la medida de su rati

o
Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0

Answer:

203.2cm

Step-by-step explanation:

De la pregunta anterior,

1 pulgada = 2.54 cm

80 pulgadas = x

Multiplicar cruzada

x = 80 × 2.54 cm

x = 203.2 centímetros

La medida de su relación es 203.2cm.

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Fully explain the solution set to the equation below.<br> 1x = -1
Lady bird [3.3K]

Answer:

The answer for x should equal: -1.

Step-by-step explanation:

To find x, we would divide, our final value, by 1 to get x. In other words, you would divide: -1 ÷ 1 to get -1 as our unknown number.

6 0
3 years ago
Someone can help me ASAPP??
bulgar [2K]

Answer: 23

Step-by-step explanation:

4 0
3 years ago
1200+0.075x&gt;=3300 what is the solution to the inequality
miskamm [114]
Solving inequalities is just like solving any other Algebraic problem...look to P.E.M.D.A.S. (Parenthesis, Exponents, Division, Addition, Subtraction). So lets take a look at this problem now.

1200 + 0.075x\geq3300


Subtract 1200 from both sides...
0.075x\geq2100

Now divide by 0.075...
x\geq28000


NOTE: If you divide or multiple by a negative number while solving inequalities, you must flip the sign. Ex: You answer would be x\leq28000 if you would've multiplied or divided by a negative.




8 0
3 years ago
A total of 70 tickets were sold for a concert and earn the organizers $804. If the cost of each ticket is either $10 or $12, how
crimeas [40]

Answer:

52 tickets cost $10 and 18 tickets cost $12

Step-by-step explanation:

10x+12y=804. (1)

x+y=70. (2)

From (2)

x=70-y

Substitute x=70-y into (1)

10x+12y=804

10(70-y)+12y=804

700-10y+12y=804

700+2y=804

2y=804-700

2y=104

y=104/2

y=52

Recall

x+y=70

x+52=70

x=70-52

x=18

52 tickets cost $10 and 18 tickets cost $12

5 0
3 years ago
Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.
alina1380 [7]

Answer:

The answer is x=a^{-1}cb^{-1}.

Step-by-step explanation:

First, it is important to recall that the group law is not commutative in general, so we cannot assume it here. In order to solve the exercise we need to remember the axioms of group, specially the existence of the inverse element, i.e., for each element g\in G there exist another element, denoted by g^{-1} such that gg^{-1}=e, where e stands for the identity element of G.

So, given the equality axb=c we make a left multiplication by a^{-1} and we obtain:

a^{-1}axb =a^{-1}c.

But, a^{-1}axb = exb = xb. Hence, xb = a^{-1}c.

Now, in the equality xb = a^{-1}c we make a right multiplication by b^{-1}, and we obtain

xbb^{-1} = a^{-1}cb^{-1}.

Recall that bb^{-1}=e and xe=x. Therefore,

x=a^{-1}cb^{-1}.

6 0
3 years ago
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