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Tamiku [17]
2 years ago
15

Geometry homework! help

Mathematics
1 answer:
Bogdan [553]2 years ago
8 0

Answer:

cos∠ABC = 12/15 = 0.80

tan∠ABC = 9/12 = 0.75

sin∠ACB = 12/15 = 0.80

cos∠ACB = 9/15 = 0.60

tan∠ACB = 12/9 = 1 1/3

Step-by-step explanation:

Find the Adjacent, Opposite, or Hypotenuse angles to the angles in the picture and fill them into the given fraction.

cos∠ABC = Adjacent/Hypotenuse = 12/15 = 4/5 = 0.80

tan∠ABC = Opposite/Adjacent = 9/12 = 3/4 = 0.75

sin∠ACB = Opposite/Hypotenuse = 12/15 = 4/5 = 0.80

cos∠ACB = Adjacent/Hypotenuse = 9/15 = 3/5 = 0.60

tan∠ACB = Opposite/Adjacent = 12/9 = 1 1/3 (1 1/3 in decimal form is 1.3 with a line on top of 3 (Bar on top of 3))

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isosceles

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Answer:

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Step-by-step explanation:

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Question 3 Determine the leg lengths between the two points: (6, -3) and (-2,4).
Shalnov [3]

Answer:

9

Step-by-step explanation:

→You can use the Pythagorean Theorem to solve this, by plugging in the numbers, like so:

\begin{gathered}a^2+b^2=c^2\\x^2+(x-3)^2=(x+3)^2\end{gathered}

a

2

+b

2

=c

2

x

2

+(x−3)

2

=(x+3)

2

x^2+x^2-6x+9=x^2+6x+9x

2

+x

2

−6x+9=x

2

+6x+9

→Subtract x^2-6x+9x

2

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2

=12x

→Subtract 12x from both sides:

x^2 -12x=0x

2

−12x=0

→Factor out x:

x(x-12)=0x(x−12)=0

→Separate, set = to 0, and solve:

\begin{gathered}x = 0\\x -12=0\end{gathered}

x=0

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→ Add 12 to both sides: x = 12x=12

→So we have 0 and 12, as our answers. However, we cannot have 0 as a side length, since this would not be possible.

→All we need to do is take 12, and plug it into the equation for the shortest leg.

\begin{gathered}x - 3=?\\12-3=9\end{gathered}

x−3=?

12−3=9

3 0
2 years ago
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