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marusya05 [52]
3 years ago
6

Use the distance formula in order to classify the to

Mathematics
1 answer:
Travka [436]3 years ago
8 0

Answer:

isosceles

Step-by-step explanation:

d=\sqrt{(4-6)^2+(6-1)^2}\\\sqrt{(-2)^2+(5)^2}\\\sqrt{4+25}\\\sqrt{29}\\\\\sqrt{(6-1)^2+(1-3)^2}\\\sqrt{(5)^2+(-2)^2}\\\sqrt{25+4}\\\sqrt{29}\\\\\sqrt{(1-4)^2+(3-6)^2}\\\sqrt{(-3)^2+(-3)^2}\\\sqrt{9+9}\\\sqrt{18}

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-7_-4 what is the answer plz help
AlexFokin [52]

the answer is

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because the -4 is less than -7

5 0
3 years ago
I need help plssssssssss
drek231 [11]

We can say that the area of the figure equals...

5.5 by 9 rectangle - 2 by 2 triangle - 2 by 5 triangle - 9 by 3.5 triangle

5.5 by 9 rectangle = 5.5 x 9 = 49.5 un²

2 by 2 triangle = 1/2 x 2 x 2 = 2 un²

2 by 5 triangle = 1/2 x 2 x 5 = 5 un²

9 by 3.5 triangle = 1/2 x 9 x 3.5 = 15.75 un²

area of figure = 49.5 un² - 2 un² - 5 un² - 15.75 un² = 26.75 un²

answer: 26.75 un²

5 0
3 years ago
Read 2 more answers
Simplity (4^-2)^5<br> A.1/4^10<br> B. 4^3<br> C.1/4^3<br> D. 4^10
Goshia [24]

Answer:

(4^{-2})^5=\dfrac{1}{4^{10}}

Step-by-step explanation:

The given expression is : (4^{-2})^5

We need to simplify the above expression.

We know that, x^{-a}=\dfrac{1}{x^a}

or

(4^{-2})^5=(\dfrac{1}{4^2})^5\\\\=\dfrac{1^5}{(4^2)^5}\\\\\because (x^b)^c=x^{b\times c}\\\\=\dfrac{1}{4^{10}}

So, the simplified form of the given expression is \dfrac{1}{4^{10}}. Hence, the correct option is (A).

5 0
3 years ago
Read 2 more answers
Now that the curve pieces are determined, use those pieces as sections of a complete coaster. By hand or by using a drawing prog
VMariaS [17]

Answer:

Could you post the rest of it pllease

Step-by-step explanation:

8 0
3 years ago
You plan to accumulate 100,000 at the end of 42 years by making the follow-
Mariana [72]

Answer:

  Y = 479.17

Step-by-step explanation:

At the end of year 14, the balance from the deposits of X can be found using the annuity due formula:

  A = P(1+r/n)((1 +r/n)^(nt) -1)/(r/n)

where P is the periodic payment, n is the number of payments and compoundings per year, t is the number of years, and r is the annual interest rate.

  A = X(1.07)(1.07^14 -1)/0.07 ≈ 24.129022X

This accumulated amount continues to earn interest for the next 28 years, so will further be multiplied by 1.07^28. Then the final balance due to deposits of X will be ...

  Ax = (24.129022X)(1.07^28) = 160.429967X

__

The same annuity due formula can be used for the deposits of Y for the last 10 years of the interval:

  Ay = Y(1.07)(1.07^10 -1)/.07 = 14.783599Y

__

Now we can write the two equations in the two unknowns:

  Ax +Ay = 100,000

  X - Y = 100

From the latter, we have ...

  X = Y +100

So the first equation becomes ...

  160.429967(Y +100) +14.783599Y = 100000

  175.213566Y +16,043.00 = 100,000

  Y = (100,000 -16,043)/175.213566 ≈ 479.17

Y is 479.17

7 0
3 years ago
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