Answer:
3825
Step-by-step explanation:
Given that we have to pick digits from the list 1, 2, 3, 4, 5, 6, 7, 8, 9 just once and build 4 digit numbers.
Find the two numbers which have the sums as the smallest
Since when the two numbers formed are the smallest the sum will be the smallest, we can pick digits in such a ways that the numbers have value the smallest. If the 1000th digit is small we would get smaller number. So let us take for first digit 1000th place 1 and second number 1000th place as 2.
Similarly for 100th now available are 3,4...8, 9 so let us take 100th digit as 3 and 5 respectively and so on.
So the numbers would be
1357 and 2468
Sum would be 
Answer:
rrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
Step-by-step explanation:
uhh
Answer:
5
Step-by-step explanation:
Tina started with $20, but had to spend $3.25 on the bat.
$20-$3.25 = $16.75, which is all she has left for rounds.
Each round costs $3.00
$16.75 divided by $3.00 comes out to 5.58 rounds, but since she can't play 1/2 a round, that means she could only play 5 rounds
5 rounds X $3.00 per round comes to $15.00
Answer:
20p
Step-by-step explanation:
Yeah becuase 4 x 5=20, and the only difference is the p so add the p onto the end and that's the answer :)
Answer:
1) First term = -105/2
2) The first option is the correct answer 9/2[ 2 + 26]
Step-by-step explanation:
It is given that,
The first term of the arithmetic sequence in which.... a27=-1/2
and the common difference is 2
<u>To find the First term
</u>
First term of an AP be a and common difference d the nth term can be written as,
an = a + (n-1)d
Here n = 27
d = 2 , a27 = -1/2
a + (26 x 2) = -1/2
a = -105/2
From the figure We get an = 3n - 1
<u>To find first term a1 and ninth term s9</u>
a1 = 3 x 1 - 1 = 2
a9 = 3x 9 - 1 = 26
<u>Sum of nth term of an AP </u>
n/2[first term + Last term]
first term a1 and Last term = 26
<u>Sum of first 9 terms S9
</u>
S9 = 9/2[ 2 + 26]
First option is the correct answer
