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LenaWriter [7]
3 years ago
11

What is the percent chance you'll roll a dice once and it will land on the #7?

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

25% chance

Step-by-step explanation:

21/36 is the chance that it will land on #7

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A line is drawn through (-4,3) and (4,3). Which describes whether or not the line represents a direct variation
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If the resultant line is a straight line,it represents a direct variation.

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4 years ago
105.25 x 70.75<br><br><br> NO LINKS!!!!!
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Answer:

7446.4375

Step-by-step explanation:

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x   70.75

-------------

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First, we will want to start with the hundredths place. multiply 5×5. We get 25. Put the 5 down and carry the 2 above 2 in 105.25. Next, we multiply 2 in 105.25 with 5 in 70.75. 2×5 is 10, then we add the carried 2, and 10+2 is 12. We put the 2 down below, and carry the 1 above 5 in 105.25. Next, we multiply the 5 in 105.25 times 5. 5×5 is 25. We then need to add the carried 1 to 25 to get 26. We put the 6 down and put the 2 over 0 in 105.25. Next, we multiply 0 in 105.25 with 5 in 70.75. 0×5 is 0, plus our carried 2 from before, so 2. We don't need to carry anything since it's only the ones digit, so we put the 0 down. Next, we multiply the 1 in 105.25 with 5 again in 70.75. 1×5=5. Since we have no carries we can put the 5 down without adding anything. If this seemed confusing, let me simplify it for you. You basically start with the bottom number's "digit". For us, that's 70.75, and 5 would be the "digit." (The last digit from the bottom number.) We then multiply this "digit" by every number from the top number's digits. For example, we'd multiply 70.75's 5, with 105.25's 5 first, then continue on going left from there. I hope this helped! If it just confused you more please let me know.  (Also remember to put a 0 when you start multiplying with your second digit on the bottom number)

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3 years ago
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irinina [24]

Answer:

x2 and 2x

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Step-by-step explanation:

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As rolling a one on a fair die has a probability of 1/6, on average it is likely that a one will be rolled around once every six rolls, therefore the game’s expected value is 0 because in six rolls one roll will yield 50 and the other five rolls -10 each granting a net total of 0.
7 0
3 years ago
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