Can someone please help me please

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

5 0

Answer:

for the first one, the solution is -pq x (3q-p) for the second question, the solution is p²q-3pq²

Step-by-step explanation:

for the first question:

-3pq²+p²q

factor out -pq from the expression

solution pq x (3q-p)

for the second question:

remove unnecessary parenthesis

2p²q-3pq²+q^3-(p²q-q^3)

when there is a "-" in front of the parenthesis, change the sign of each term in parenthesis

2p²q-3pq²+q^3-(p²q-q^3)

then, eliminate the opposites

2p²q-3pq²-p²q

collect the terms

p²q-3pq²

finally, you got your answer,

p²q-3pq²

I hope this helped!

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