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Amanda [17]
3 years ago
15

Can someone please help me please

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

for the first one, the solution is -pq x (3q-p) for the second question, the solution is p²q-3pq²

Step-by-step explanation:

for the first question:

-3pq²+p²q

factor out -pq from the expression

solution pq x (3q-p)

for the second question:

remove unnecessary parenthesis

2p²q-3pq²+q^3-(p²q-q^3)

when there is a "-" in front of the parenthesis, change the sign of each term in parenthesis

2p²q-3pq²+q^3-(p²q-q^3)

then, eliminate the opposites

2p²q-3pq²-p²q

collect the terms

p²q-3pq²

finally, you got your answer,

p²q-3pq²

I hope this helped!

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The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118   .

In the question ,

it is given that ,

the probability of committing at least , type I error is = 0.7

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let the number of test be n ,

the above mentioned situation can be written as

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which is written as ,

1 - (1 - 0.01)ⁿ ≥ 0.7

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(0.99)ⁿ ≤ 0.3

On further simplification ,

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Therefore , the number of tests are 118 .

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Step-by-step explanation:

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Step-by-step explanation:

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