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2 years ago

Answer question below answer question below

Mathematics

1 answer:

podryga [215]2 years ago

5 0

Answer:

r = sqrt(11)

Step-by-step explanation:

Area of sector, A = (theta) r^2/ 2 = 11 cm^2

Perimeter of sector, p= r theta+2r

Length of arc AB, a= r theta

We are given that p = 2a, so equate

r theta + 2r = 2(r theta)

2r = r( theta )

theta = 2 (radians)

Solve for r from area

Area = (theta) r^2 /2 = 11

substitute theta = 2

2 r^2 /2 =11

r^2 = 11

r = sqrt(11)

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--------------------------------------------------------------------------
Equation
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$y - 9 = - \dfrac{1}{2} (x + 2)$

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Rearrange the equation
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 y - 9 = - \dfrac{1}{2}x - 1 \\ \\
 y - 9 + 9 = - \dfrac{1}{2}x - 1 + 9 \ \Longleftarrow \text{add 9 to both side} \\ \\
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(*the slope of the perpendicular line is the <span>negative reciprocal of the slope of line)</span>

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Substitute slope into equation y = mx + c
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Find y-intercept
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