2 years ago

Answer question below answer question below

Mathematics

1 answer:

podryga [215]2 years ago

5 0

Answer:

r = sqrt(11)

Step-by-step explanation:

Area of sector, A = (theta) r^2/ 2 = 11 cm^2

Perimeter of sector, p= r theta+2r

Length of arc AB, a= r theta

We are given that p = 2a, so equate

r theta + 2r = 2(r theta)

2r = r( theta )

theta = 2 (radians)

Solve for r from area

Area = (theta) r^2 /2 = 11

substitute theta = 2

2 r^2 /2 =11

r^2 = 11

r = sqrt(11)

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40 points for this question! Algebra 2. With all explanation, please!

const2013 [10]

You will need three roots for this, so we have
Let x = -30, -10 and +20
So the factors will be (x+30)(x+10)(x-20)
The divide it to 100, this will help bring the peak up and down
So the polynomial function R(x) will become
1/100 * (x+30)(x+10)(x-20)
R(x) = 1/100 * (x+30)(x+10)(x-20)

Finding the X-intercept:
Let R(x) = 0 and solve for x.
1/100 * (x+30)(x+10)(x-20) = 0
x = -30, -10, 20 are the x-intercepts.

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2 years ago

Pleases help quick please

Solnce55 [7]

Answer:

1 and 2

Step-by-step explanation:

$\sqrt{2}$ = 1.41421356237