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Ivan
3 years ago
10

During mitosis, one cell creates:

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

two identical cells

Explanation:

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Questions 25,26 28, 29
dybincka [34]
I believe number 26 if in correct is product.
3 0
3 years ago
Read 2 more answers
The temperature of a sample of water from the faucet increases from 22.7°C to 48.9°C when 3,710J are applied through electric sh
MakcuM [25]

Answer:

33.8.

Explanation:

Hello,

In this case, since the used equation is:

Q=mCp(T_2-T_1)

Whereas the specific heat is 4.184 J/(g°C), we compute the mass as follows:

m=\frac{Q}{Cp(T_2-T_1)}

Thus, the mass turns out:

m=\frac{3,710J}{4.184\frac{J}{g\°C} (48.9-22.7)\°C}\\\\m=33.8g

And without units:

33.8.

Best regards.

8 0
3 years ago
What is the entropy change for freezing 2.71 g of C2H5OH at 158.7 K? ∆H = −4600 J/mol. Answer in units of J/K.
Ira Lisetskai [31]

Answer:

-1.71 J/K

Explanation:

To solve this problem we use the formula

ΔS = n*ΔH/T

Where n is mol, ΔH is enthalpy and T is temperature.

ΔH and T are already given by the problem, so now we calculate n:

Molar Mass C₂H₅OH = 46 g/mol

2.71 g C₂H₅OH ÷ 46g/mol = 0.0589 mol

Now we calculate ΔS:

ΔS = 0.0589 mol * −4600 J/mol / 158.7 K

ΔS = -1.71 J/K

4 0
3 years ago
What is the balanced chemical equation for caffeine?
Olegator [25]
<span>C8H10N4O2 
Or do you want it in a reaction problem? 


</span>
8 0
3 years ago
What is the electron configuration for vanadium (V)? The Periodic Table A. 1s22s22p63s23p64s24d3 B. 1s22s22p63s23p63d5 C. 1s22s2
kramer

The electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3 (option D).

<h3>What is electronic configuration?</h3>

Electronic configuration is the the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.

Vanadium is the 23rd element on the periodic table and has chemical symbol V with atomic number 23. It is a transition metal, used in the production of special steels.

This suggests that the electronic configuration of Vanadium will be written as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3

Therefore, the electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3.

Learn more about electronic configuration at: brainly.com/question/14283892

#SPJ1

5 0
2 years ago
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