Answer:
Cobaltous Nitride,I think so anyway.......
Answer:
Mass of seawater = 512.5 gram
Explanation:
Given:
Volume of seawater = 500 ml
Density of seawater = 1.025 g/ml
Find:
Mass of seawater
Computation:
Mass of seawater = Volume of seawater × Density of seawater
Mass of seawater = 500 × 1.025
Mass of seawater = 512.5 gram
Answer:
MM = 5,521.54 g/mol
Explanation:
To solve this, we need to use the expression for osmotic pressure which is the following:
π = MRT (1)
Where:
M: Concentration of the solution
R: gas constant (0.082 L atm/ mol K
T: temperature in K
25 °C in Kelvin is: 25 + 273.15 = 298.15 K
Now, we do not have the concentration of the solution, but we do have the mass. and the concentration can be expressed in terms of mass, molar mass and volume:
Concentration (M) is:
M = n/V (2)
and n (moles) is:
n = m/MM (3)
Therefore, if we replace (2) and (3) in (1) we have:
π = mRT/V*MM
Solving for MM we have:
MM = mRT/πV (4)
All we have to do now, is replace the given data and we should get the value of the molar mass:
MM = 6.143 * 0.082 * 298.15 / 0.1 * 0.272
MM = 150.1859 / 0.0272
<em>MM = 5,521.54 g/mol</em>
<em>This is the molar mass.</em>
The physical state of fluorine at room temperature is a gas, a pale yellow in colour
