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3 years ago

HELPPPPPPPPP ME PLEASE????!!?!?!?!?!

Mathematics

1 answer:

Gnesinka [82]3 years ago

4 0

Answer:

More than half

Step-by-step explanation:

Half is 0.5 this is 0.785 approximately 0.280 more or > 0.5

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How many teaspoons are in 1/4 cups

mojhsa [17]

Answer:

12 U.S teaspoons are in 1/4 cups.

The Formula is to multiply the volume value by 48.

So Since a 1/4 us cup=0.25 we can multiply this by 48.

0.25*48=12

So our awnser is 12 teaspoons

5 0

3 years ago

><br> 40 cm out of 3.5m .

vovikov84 [41]

Answer:

Your answer is 11.42

Step-by-step explanation:

hope it helps

3 0

3 years ago

The measure of an angle is 34°.

Volgvan

Answer:

146 is the answer because 180 - 34 = 146. And I did the test and it was right.

I hope this helped:)

3 0

3 years ago

Read 2 more answers

Arrange the following and ascending and descending order first one is 1 by 12 1 by 23 1 by 5 1 by 7 1 by 50 1 by 9 1/17

Nonamiya [84]

Answer:

Ascending order is given by

1/50<1/23<1/17<1/12<1/9<1/7<1/5

Descending order is given by

1/5>1/7>1/9>1/12>1/17>1/23>1/50

Step-by-step explanation:

We are given that

1/12,1/23,1/5,1/7,1/50,1/9,1/17

We have to arrange the numbers in ascending and descending order.

LCM of 12,23,5,7,50,9,17

$23\times 5\times 12\times 7\times 50\times 17\times 9$

=73899000

$\frac{1}{12}\times \frac{6158250}{6158250}=\frac{6158250}{73899000}$

$\frac{1}{23}\times \frac{3213000}{3213000}=\frac{3213000}{73899000}$

$\frac{1}{5}\times \frac{14779800}{14779800}=\frac{14779800}{73899000}$

$\frac{1}{7}\times \frac{10557000}{10557000}=\frac{10557000}{73899000}$

$\frac{1}{50}\times \frac{1477980}{1477980}=\frac{1477980}{73899000}$

$\frac{1}{9}\times \frac{8211000}{8211000}=\frac{8211000}{73899000}$

$\frac{1}{17}\times \frac{4347000}{4347000}=\frac{4347000}{73899000}$

14779800>10557000>8211000>6158250>4347000>3213000>1477980

Therefore,

Ascending order is given by

1/50<1/23<1/17<1/12<1/9<1/7<1/5

Descending order is given by

1/5>1/7>1/9>1/12>1/17>1/23>1/50

5 0

3 years ago

The time, in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters

Serhud [2]

Answer:

$d=\dfrac{t^2}{a}$

Step-by-step explanation:

The time in seconds, required for an object accelerating at a constant rate of a meters/second to travel a distance of d meters is given by this equation.

t = va

We need to find the expression for d in terms of t and a.

As velocity = distance/time

$t=\dfrac{d}{t}a\\\\t^2=da\\\\d=\dfrac{t^2}{a}$

So, the distance d is $\dfrac{t^2}{a}$ .

8 0

3 years ago