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FromTheMoon [43]
3 years ago
11

Find the perimeter of a isosceles right triangle having area of 200 CM square​

Mathematics
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

The perimeter of the isosceles right triangle is 68.28 cm.

Step-by-step explanation:

Given;

area of the isosceles right triangle, A = 200 cm²

let the two equal sides of the triangle = base (b) and height (h)

Area of the isosceles right triangle is calculated as;

A= \frac{1}{2} bh \\\\But, b = h\\\\A = \frac{1}{2} b^2\\\\200 = \frac{1}{2} b^2\\\\400 = b^2\\\\\sqrt{400}  = b\\\\20 \ cm = b

let the hypotenuse side of the isosceles right triangle = c

c² = b² + h²

c² = 20² + 20²

c² = 800

c = √800

c = 28.28 cm

The perimeter of the isosceles right triangle is calculated as;

P = b + h + c

P = 20 cm + 20 cm + 28.28 cm

P = 68.28 cm

Therefore, the perimeter of the isosceles right triangle is 68.28 cm.

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Given ƒ(x) = 9x + 54, find x when ƒ(x) = 18. <br> A)−6 B)−4 C)3 D)8
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