Answer:
The perimeter of the isosceles right triangle is 68.28 cm.
Step-by-step explanation:
Given;
area of the isosceles right triangle, A = 200 cm²
let the two equal sides of the triangle = base (b) and height (h)
Area of the isosceles right triangle is calculated as;
let the hypotenuse side of the isosceles right triangle = c
c² = b² + h²
c² = 20² + 20²
c² = 800
c = √800
c = 28.28 cm
The perimeter of the isosceles right triangle is calculated as;
P = b + h + c
P = 20 cm + 20 cm + 28.28 cm
P = 68.28 cm
Therefore, the perimeter of the isosceles right triangle is 68.28 cm.
Answer:
It's position at time t = 5 is 593.
Step-by-step explanation:
The velocity v(t) is the integral of the acceleration a(t)
The position s(t) is the integral of the velocity v(t)
We have that:
The acceleration is:
Velocity:
K is the initial velocity, that is v(0). Since V(0) = 13, K = 13
Then
Position:
Since s(0) = 3
What is its position at time t=5?
This is s(5).
It's position at time t = 5 is 593.
Answer:
Step-by-step explanation:
1) divide each term in the numerator by the term in denominator:
(remember when dividing subtract the smaller exponent from larger exponent
for example: say a is the larger exponent, do
x^4/x=x^3
5x^3/x=5x^2
3x^2/x=3x
so
x^3+5x^2+3x
hope this helps!