Answer:
8x^2 + 5y + 1
Step-by-step explanation:
1 + x^2 - 3 + 2y + 7x^2 + 3 + 3y
group like terms
= x^2 + 7x^2 + 2y + 3y + 1 - 3 + 3
add similar items
= 8x^2 + 2y + 3y + 1 - 3 + 3
add similar items
= 8x^2 + 5y + 1 - 3 + 3
= 8x^2 + 5y + 1
Step-by-step explanation: To solve this absolute value inequality,
our goal is to get the absolute value by itself on one side of the inequality.
So start by adding 2 to both sides and we have 4|x + 5| ≤ 12.
Now divide both sides by 3 and we have |x + 5| ≤ 3.
Now the the absolute value is isolated, we can split this up.
The first inequality will look exactly like the one
we have right now except for the absolute value.
For the second one, we flip the sign and change the 3 to a negative.
So we have x + 5 ≤ 3 or x + 5 ≥ -3.
Solving each inequality from here, we have x ≤ -2 or x ≥ -8.
Based on the ratio of boys/girls We can infer that the only possibility for Ellen's math class would be answer B. 14/21
Unfortunately, Tashara, you have not provided enuf info from which to calculate the values of a and b. If you were to set <span>F(x)=x(x+a)(x-b) = to 0, then:
x=0,
x=-a
x=-b
but this doesn't answer your question.
Double check that you have shared all aspects of this question.</span>