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pishuonlain [190]
3 years ago
6

What is the length of the diameter for the circle having equation of x2 + y2 + 10x - 24y + 69 = 0

Mathematics
1 answer:
gladu [14]3 years ago
4 0

Answer:

Step-by-step explanation:

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How to do 3/2b+1/5b=17 ?
guajiro [1.7K]

Answer:

b = 10

Explanation:

Lets start by combining like terms (b):

3/2b + 1/5b

to combine these fractions you must get them to both have the same denominator:

3/2 · 5/5 = 15/10     multiply top and bottom by other fractions denominator

1/5 · 2/2 = 2/10       multiply top and bottom by other fractions denominator

15/10 + 2/10 = 17/10

17/10b = 17

Now we want to get the b to be by itself, so lets first multiply both sides by 10:

17b = 170

Now lets divide both sides by 17:

b = 10

Hope this helped!

7 0
3 years ago
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Parallelogram ABCD has vertices A(-2, -5 1/2), B(-4, -5 1/2),C(-3, -2), and D(-1, 2). Find the vertices of parallelogram A'B'C'D
Sever21 [200]
A= (-2,-7 1/2)
B= (-4,-7 1/2)
C= (-3,-4)
D= (-1,0)
4 0
3 years ago
Will someone please help me understand this?
mario62 [17]

Option A:

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Solution:

In the quadrilateral, the coordinates of J is (1, 6) and L is (7, 3).

So that, x_1=1, y_1=6, x_2=7, y_2=3

To find the length of the diagonal JL.

Using distance formula:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

d=\sqrt{(3-6)^2+(7-1)^2}

d=\sqrt{(-3)^2+(6)^2}

d=\sqrt{9+36}

d=\sqrt{45}

d=\sqrt{3^2\times 5}

d=3\sqrt{ 5} units

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Option A is the correct answer.

7 0
3 years ago
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