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Elanso [62]
3 years ago
6

Which scenario describes a relationship of mutualism?

Biology
2 answers:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

b

Explanation:

Alex_Xolod [135]3 years ago
5 0

Answer:

hello the answer is B hope this helps

Explanation:

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A scientist is studying a plant species in which the flower color genes are codominant the scientist crosses a plant with red fl
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In co dominance, both alleles show. Thus, the filial, F1, generation, will most likely be white with red spots/speckles. See image below.

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3 years ago
Whats 200 to the power of ten
jeyben [28]

Answer:

1.024e+23

Explanation:

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3 years ago
Which the most inclusive taxonomic grouping a)order b) species c) genus d) kingdom
zimovet [89]

The correct answer is d) kingdom.

Taxonomy is the branch of biology which deals in categorizing and naming of species. The modern taxonomic classification system consists of the eight taxonomic groups. These are Domain, Kingdom, Phylum, Class, Order, Family, Genus, and Species. The domain is the most inclusive of the all taxonomic groups and species is the least inclusive.  It is because every different species has a unique features. In this question domain is not in the option, thus Kingdom is the correct answer As it includes different Phylum, Class, Order, Family, Genus, and Species.

3 0
3 years ago
Read 2 more answers
Because they alter the reading frame of all base-pair triplets, base-pair additions and deletions are collectively referred to a
Rom4ik [11]

Answer:

The correct answer is option c. "frameshift mutations".

Explanation:

The reading frame of a gene is based on base-pair triplets, starting from the start codon until the ribosome encounters with the end codon. Base-pair additions and deletions are collectively referred to as frameshift mutations because they alter the reading frame of the gene. Base-pair additions and deletions break down the original sequence of the gene triplets, which alters the open reading frame and usually results in the production of non active proteins.

7 0
3 years ago
The retinoblastoma protein, pRB, is a tumor-suppressor protein that controls the G1/S cell-cycle checkpoint. While pRB is presen
gladu [14]

Answer:

1. pRB phosphorylated: The cell will not remain in G1 phase i.e. it will enter S phase because pRB will be degraded.

2. pRB not phosphorylated: The cell will remain in G1 phase i.e. will not enter S phase because pRB will remain bound to E2F.

3. pRB bound to E2F: The cell will remain in G1 phase i.e. will not enter S phase.

4. pRB not bound to E2F: The cell will not remain in G1 phase i.e. it will enter S phase.

5. E2F bound to DNA: The cell will not remain in G1 phase i.e. it will enter S phase.

6. CDK4 bound to Cyclin D1:  The cell will not remain in G1 phase i.e. it will enter S phase.

Explanation:

Retinoblastoma protein, pRB supresses tumor by regulating cell cycle progression in G1 phase. When a transcription factor known as E2F is bound to pRB the cell remains in G1 phase and did not proceed further to enter S phase. But as soon as pRB becomes phosphorylated, E2F becomes free and causes gene expression of cyclin E and and cyclin A which are required in progression of cell cycle from G1 phase to S phase.

<u>Signaling involved in cell cycle progression from G1 phase to S phase. </u>

When a cell is unstimulated, pRB is bound to E2F but G1 phase specific growth factors induce the expression of cyclin D through Ras-MAP kinase pathway.

Synthesis of cyclin D leads to the activation of CDK-4 which is a serine-threonine kinase. This kinase causes phosphorylation of pRB which results in the degradation of pRB.

Because of degradation of pRB, <u>E2F becomes free</u> and leads to the expression of cyclin E and and cyclin A which are S phase specific cyclins. This is how cell progresses from G1 phase to S phase.

E2F is a transcription factor which causes expression of S phase specific cyclins i.e. cyclin E and and cyclin A. So, E2F bound to DNA will result in cell cycle progression from G1 phase to S phase.

7 0
3 years ago
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