Which is a zero of the quadratic function f(x) = 16x?? + 32x - 9?

Mathematics

1 answer:

STALIN [3.7K]2 years ago

6 0

Answer:

f(x) = 16x2 + 32x - 9

To find the "zeros", set f(x) = 0:

0 = 16x2 + 32x - 9

The equation is solvable by factoring or by using the quadratic formula. The factors (use the "ac" method) are:

0 = (4x-1)(4x+9)

x = 1/4 = 0.25 and x = -9/4 = -2.25

Step-by-step explanation:

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