Which is a zero of the quadratic function f(x) = 16x?? + 32x - 9?
1 answer:
Answer:
f(x) = 16x2 + 32x - 9
To find the "zeros", set f(x) = 0:
0 = 16x2 + 32x - 9
The equation is solvable by factoring or by using the quadratic formula. The factors (use the "ac" method) are:
0 = (4x-1)(4x+9)
x = 1/4 = 0.25 and x = -9/4 = -2.25
Step-by-step explanation:
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