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ratelena [41]
1 year ago
13

Solve 3x + 5 = 2x + 7

Mathematics
1 answer:
Pie1 year ago
5 0

Answer:

x = 2

Step-by-step explanation:

3x + 5= 2x + 7

<em>Subtract 2x from both sides</em>

3x + 5 −2x = 7

<em>Combine 3x and −2x to get x</em>

x + 5 = 7

<em>Subtract 5 from both sides</em>

x = 7 − 5

<em>Subtract 5 from 7 to get 2</em>

x = 2

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What is the fifth term of the geometric sequence? 5, 15 , 45, ...
Virty [35]

The geometry sequence has the equation a(n)=5(3^{n-1}).

The 5 represents the first number of the sequence and the 3 represents the common ratio.

a(5) = 5(3^{5-1})=5(3^{4})=5(81)=405

answer: 405

6 0
3 years ago
The surface areas of two similar solids are 384 yd squared and 1057 yd squared The volume of the larger solid is 1795. What is t
Arturiano [62]
This is the concept of scale factors, we are required to calculate for the volume of the smaller solid if the larger solid has a volume of 1975.
Area scale factor=(linear scale factor)^2
thus;
Area scale factor=(area of larger solid)/(area of smaller solid)=1057/384
linear scale factor=√(1057/384)=5.7019
the volume scale factor=(linear scale factor)^3=[volume of larger solid]/[volume of smaller solid]
The volume scale factor=(5.7019)^3=185.3772
therefore;
volume of smaller solid=[volume of larger solid]/[volume scale factor]

=1795/185.3772
=9.683 
The answer is 9.683 yd^3

5 0
3 years ago
Find an equation that is perpendicular to the x-axis and passes through the point (7,13)
rjkz [21]

Answer:

x = 7

Step-by-step explanation:

A line perpendicular to the x- axis is a vertical line parallel to the y- axis.

The equation of a vertical line is

x = c

where c is the value of the x- coordinates the line goes through

The line goes through (7, 13) with x- coordinate of 7, thus

x = 7 ← equation of perpendicular line

4 0
3 years ago
Someone help me do the first problem so that I can do the rest
Novay_Z [31]

Answer:

C = 69.1 ft

Step-by-step explanation:

The circumference is given by

C = 2*pi*r

C = 2* 3.14 * 11

C =69.08

Round to the nearest tenth

C = 69.1 ft

7 0
3 years ago
Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of
Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

\triangle ABC \sim \triangle NMP

MP\parallel BC

MP=\frac{BC}{2}

By the property of similar triangles,

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}

Hence proved.

5 0
3 years ago
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