Which set of ordered pairs does not represent a function?

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is $\hat p_1$ = 1020/1272 = 85/106 = $0.8\overline {0188679245283}$ ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is $\hat p_2$ = 5343/6238 ≈ 0.8565

c) We have the following two way table;

$\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}$

$The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780$

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

$95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}$

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

$95 \% \ CI \approx 0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155$

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0

3 years ago

dolores and four friends went to a buffet dinner.The total cost was at most $130 including the $20 dollar tip they left.How much

Levart [38]

So the actual meal was at most 130 dollars they paid minus the 20 dolars tip: 130-20=110 dollars.

it was 5 people: Dolores+5 friends, who presumably all paid the same (buffet).

then we have to divide the 110 among the 5 people: it's 110/5=22

so each of them paid at most 22 dollars:

x (the amount they paid)≤22

5 0

4 years ago

Find the missing term (need help)

katen-ka-za [31]

Answer:

x² - 10x + 34

Step-by-step explanation:

given the roots are x = 5 ± 3i then the factors are

(x - (5 + 3i))(x - (5 - 3i))

= (x - 5)² - 9i² ← expand (x - 5)²

= x² - 10 x + 25 + 9 → [ i² = - 1 ]

= x² - 10x + 34

the missing term is 10x

7 0

4 years ago

Given: x + 5 ≥ 10. Choose the graph of the solution set.

gizmo_the_mogwai [7]

Let's solve the inequality. Subtract 5 from both sides. The result will be

<span>x ≥ 5. This states, "x is equal to or greater than 5."
</span>
Plot 5 on the number line, using a dark solid dot. Then draw an arrow from that point to the right.

3 0

3 years ago

Read 2 more answers

Simplify the expression to a polynomial in standard form:

lukranit [14]

Answer:

$-x^3+7x^2-6x-18$