Please help 15 points

Mathematics

1 answer:

Gre4nikov [31]3 years ago

7 0

Answer:

i really don’t know ,

sorry , I’m so sorry

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Find the equation (in standard form) whose center is (5, -3) and goes through (2, 5).

yanalaym [24]

We can write this as

(x - 5)^2 + (y + 3)^2 = r^2

where r = radius

Plugging in the point (2,5) we have

(2-5)^2 + (5+3)^2 = r^2
r^2 = 9 + 64 = 73
so the required equation is

(x - 5)^2 + (y + 3)^2 = 73

3 0

3 years ago

What percent of 98is14

Ivanshal [37]

Answer:

14.29

Step-by-step explanation:

14:98*100 =

(14*100):98 =

1400:98 = 14.29

4 0

3 years ago

Is the relationship shown by the data linear? If so, model the data with an equation.

zhenek [66]

Answer:

Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9) is

Linear Relationship i.e $y-5=2(x+7)$

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -7, 5 )

point B( x₂ , y₂) ≡ (-5, 9)

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

$(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\$

Substituting the given values in a above equation we get

$(y-(5))=(\frac{9-(5)}{-5--7})\times (x--7)\\ \\(y-5)=\frac{4}{2}(x+7)\\\\y-5=2(x+7)...............\textrm{which is the required equation of the line AB}$