Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer:
her language arts hw takes longer and it takes 2/9 hr longer
Step-by-step explanation:
first of all, 4/9 > 2/9
4/9-2/9=2/9
Answer:
three thousand and ninty-four
Step-by-step explanation:
I think thats the right answer :)
Answer:
f(x) = (x+6)² - 10
Step-by-step explanation:
To write the equation in vertex form we, we need to use completing square method.
f(x) = x²+ 12x + 26 = (x² + 2*x*6 + 6²) - 6² + 26 = (x+6)² -36 + 26 =
= (x+6)² - 10
f(x) = (x+6)² - 10
