I’m not sure if this is actually a strategy but can I get brainliest please. If I’m not allowed to use a calculator then I would covert the decimals to fractions. I would covert them to the simplest fractions before multiplying so that the answer is as closest to its simplest form as possible.
50+5x=total profit. To get 10% of 50 you would multiply .1x50= 5. X would be the amount of days past so 10th day = $100 total but $50 profit and 30th day = $200 total but $150 profit
Answer:
z - 2*x - 1.5*y = 0 maximize
subject to:
3*x + 5*y ≤ 800
8*x + 3*y ≤ 1200
x, y > 0
Step-by-step explanation:
Formulation:
Kane Manufacturing produce x units of model A (fireplace grates)
and y units of model B
quantity Iron cast lbs labor (min) Profit $
Model A x 3 8 2
Model B y 5 3 1.50
We have 800 lbs of iron cast and 1200 min of labor available
We need to find out how many units x and units y per day to maximiza profit
First constraint Iron cast lbs 800 lbs
3*x + 5*y ≤ 800 3*x + 5*y + s₁ = 800
Second constraint labor 1200 min available
8*x + 3*y ≤ 1200 8*x + 3*y + s₂ = 1200
Objective function
z = 2*x + 1.5*y to maximize z - 2*x - 1.5*y = 0
x > 0 y > 0
The first table is ( to apply simplex method )
z x y s₁ s₂ Cte
1 -2 -1.5 0 0 0
0 3 5 1 0 800
0 8 3 0 1 1200
When it’s negative change it to a positive and vice versa. 0 stays 0
Answer:
13x - 8y
Step-by-step explanation:
Step 1: Write expression
(6x - y) + (7x - 7y)
Step 2: Combine like terms
13x - 8y
