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3 years ago

8

You are wrapping a cube shape present that is 1.5 ft tall. How much wrapping paper will you need to wrap the entire present? I'l

l give brainliest

1 answer:

xz_007 [3.2K]3 years ago

5 0

Answer:

the answer is going to be 6.0

Step-by-step explanation:

1.5+1.5=3, 3+3=6

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The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

5 0

3 years ago

Add. (−x^3 + 26x^2 − 7x−13) + (6x^4 − x^3 + 8x+27) Express the answer in standard form. Enter your answer in the box.

mamaluj [8]

$6 x^{4} -2 x^{3} +26 x^{2} +x+14$
hope this helps

5 0

3 years ago

Simplify the following:

Ket [755]

Answer:

For the first question:

$\sqrt{\frac{15x}{x^3}}\\= \sqrt{\frac{15}{x^2}}\\= \frac{\sqrt{15}}{x}\\$

And the second

$\frac{\sqrt{x^2}}{\sqrt{x^3}}\\= (x^2)^{\frac{1}{2} }(x^3)^{\frac{-1}{2} }\\= x^1 \times x^{\frac{-3}{2} }\\= x^{\frac{2}{2}} \times x^{\frac{-3}{2} }\\= x^{-\frac{1}{2}}\\= \frac{1}{\sqrt{x}}$

5 0

3 years ago

Read 2 more answers

Solve the system of equations: *

Vitek1552 [10]

Answer:

One solution: (6,0)

Step-by-step explanation:

4(6)+2(0)=24

6+0=6

6 0

3 years ago

The ratio of blue chairs to red chairs in miss Vickers class is 2 to 5. which of the following cannot represent the total number

ollegr [7]

Answer:

1 to 4 chairs

Step-by-step explanation:

4 0

3 years ago