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3 years ago

The perimeter of a rectangular garden is 38 feet. If the length is 5 feet longer than the width, find the width of the

Mathematics

1 answer:

son4ous [18]3 years ago

4 0

Answer:

Step-by-step explanation:

L and W are the length and width of the garden, respectively.

perimeter = 2L+2W = 38 ft

L+W = 19

the length is 5 ft longer than the width

L = W+5

substitution

(W+5)+W = 19

2W+5 = 19

W = 7

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Solve for x: |x| − 8 = −5

hjlf

X= 3 and x= -3 that should be the correct answer

3 0

2 years ago

A study on how circus ticket pricing influences ticket sales shows that there is an average increase of 4 people for every $3 de

____ [38]

Let the price of a ticket be originally T dollars, and the number of clients be N.

let the price decrease by x 3-dollars.

"there is an average increase of 4 people for every $3 decrease on the price of the ticket."

means:

if the price is decreased by 1-3$:
then N become N+4, and T becomes T-3

if the price is decreased by 2-3$:
then N become N+4+4=N+2*4, and T becomes T-3-3=T-2*3

So if the price is decrease by x-3 dollars:

N becomes N+4x, and T becomes T-3x

"A circus owner sells an average of 340 tickets when the price of a ticket is $75."

In this case N=340, and T=75$

If the owner does not change the price ticket, x=0, the revenue is 340*75,

If the owner decreases the price of the tickets by x-3$, then the revenue will be
(N+4x)(T-3x)=(340+4x)(75-3x) dollars,

If R is the function of the revenue depending on x, then

R(x)=(340+4x)(75-3x) dollars

Answer: R(x)=(340+4x)(75-3x) dollars

8 0

3 years ago

SOMEONE PLEASEEEEW HELP ME OUTTT

garik1379 [7]

Answer:

By Double splitting method

=> 2x²-7x+5

=> 2x²-2x-5x+5

=>2x(x-1)-5(x-1)

x=5/2
x=1

______________

Hope it helps

-------☆ﾟ.･｡ﾟƒöᏝϗʆѻʁᶥąռ¹₃

4 0

3 years ago

Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.

il63 [147K]

Answer:

The minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

Step-by-step explanation:

Given function is $f(x) = 0.15(x + 1)^2 - 3$

We need to find the maximum value or the minimum value for the function.

Now, differentiate $f(x) = 0.15(x + 1)^2 - 3$ w.r.t $x$ .

$f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\$

$f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)$

Now, we will equate $f'(x)=0$ to find critical point.

$0.3(x+1)=0\\x=-1$

Plug this critical point in to the function $f(x) = 0.15(x + 1)^2 - 3$ we get,

$f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3$

Also, $f''(x)=0.3$ which is positive, We have minimum value.

So, the minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

7 0

3 years ago

Of all of the individuals who develop a certain rash, suppose the mean recovery time for individuals who do not use any form of

VashaNatasha [74]

Answer:

z(s) is in the rejection region. We reject H₀. We dont have enought evidence to support that the cream has effect over the recovery time

Step-by-step explanation:

Sample information:

Size n = 100

mean x = 28,5

Population information

μ₀ = 30

Standard deviation σ = 8

Test Hypothesis

Null Hypothesis H₀ x = μ₀

Alternative Hypothesis Hₐ x < μ₀

We assume CI = 95 % then α = 5 % α = 0,05

As the alternative hypothesis suggest we should develop a one tail-test on the left ( we need to find out if the cream have any effect on the rash), effects on the rash could be measured as days of recovery

A z(c) for 0,05 from z-table is: z(c) = - 1,64

z(s) = ( x - μ₀ ) / σ/√n

z(s) = ( 28,5 - 30 ) / 8/√100

z(s) = - 1,5 * 10 / 8

z(s) = - 1,875

Comparing z(s) and z(c)

|z(s)| < |z(c)| 1,875 > 1,64

z(s) is in the rejection region. We reject H₀. We dont have enought evidence to support that the cream has effect over the recovery time

3 0

3 years ago