A.) 3.2 pounds package has a shipping cost of $4.13. We can't use the cost assigned to 3 lbs because the package is over 3 lbs but it is not over 4 lbs so we use the cost of 4lbs.
b) It is better to use a line graph where x values represent the weight in pounds and the y values represent the cost.
c) f(x) = 2.69 + 0.48(x-1)
d) domain is the x values; range is the y values
Answer:
D
Step-by-step explanation:
Simplify the following:
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer: (-5 i t^4 - 14)/7
Answer:
1 <u> 5 </u> <u>10 </u> <u>10</u> <u>5</u> 1 Row 5
1 <u>6</u> <u>15</u> <u>20</u> <u>15</u> <u>6</u> 1 Row 6
Recursive relationship:
Each row has number of positions = row number + 1. The Row 0 is always 1.
The first and last number in each row is 1, the number in the second position and the penultimate corresponds to the number of the row. The middle numbers correspond to the sum of the two numbers in the top row. The resulting number from the addition is located in the middle of the numbers added in the next row.
Step-by-step explanation:
The pascal's triangle
* Row 0 = 1
* Row 1 = 1 1
1 Row 0
1 1 Row 1
Since there are only two positions, the first and last are 1.
*Row 2 = 1 _ 1
1 Row 0
1 1 Row 1
1 2 1 Row 2
2 is the sum of 1 + 1 and we place it in the next row between the added numbers 1 and 1.
* Row 3 = 1 _ _ 1
1 Row 0
1 1 Row 1
1 <u>2</u> <u>1 </u> Row 2
1 3 <u>3</u> 1 Row 3
1 + 2 = 3 (the row number and the and adding the numbers from the previous row)
* Row 4 = 1 _ _ _ 1
1 Row 0
1 1 Row 1
1 2 1 Row 2
1 <u>3</u><u> </u> <u>3</u> 1 Row 3
1 4 <u>6</u> 4 1 Row 4
1 + 3 = 4 (the row number)
3 +3 = 6
* Row 5 = 1 _ _ _ _ 1
1 Row 0
1 1 Row 1
1 2 1 Row 2
1 3 3 1 Row 3
1 4 6 4 1 Row 4
1 5 10 10 5 1 Row 5
1 + 4 = 5
4 + 6 = 10
* Row 6 = <u>1</u> _ _ _ _ _ <u>1</u>
1 Row 0
1 1 Row 1
1 2 1 Row 2
1 3 3 1 Row 3
1 4 6 4 1 Row 4
1 5 <u>10</u> <u> 10 </u> 5 1 Row 5
1 6 15 <u>20</u> 15 6 1 Row 6
1 + 5 = 6
5 + 10 = 15
10 + 10 = 20