Answer:
Step-by-step explanation:
x
=
0
<span><span>Make it a solid line for y≤ or y≥, and a dashed line for y< or y>
</span><span>Shade above the line for a "greater than" (y> or y≥)
or below the line for a "less than" (y< or y≤).
So, the answer is A) </span></span><span>x + 4y ≥ −4
</span><span>x + 4y ≥ −4
4y </span>≥ -x - 4
y ≥ -x/4 - 1
y < - 8 or y > 4
inequalities of the form | x | > a always have solutions of the form
x < - a or x > a
we have to solve
y + 2 < - 6 or y + 2 > 6
y + 2 < - 6 ( subtract 2 from both sides )
y < - 8
or
y + 2 > 6 ( subtract 2 from both sides )
y > 4
these can be combined using interval notation
y ∈ (- ∞, - 8 ) ∪ (4, ∞ )
As a check
substitute chosen values of x from each interval
y = - 10 : | - 10 + 2 | = | - 8 | = 8 > 6 this is true
y = 12 : | 12 + 2 | = | 14 | = 14 > 6 which is also true
Answer:
3
Step-by-step explanation:
Answer:
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Step-by-step explanation:
