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3 years ago

What I Can Do

Mathematics

1 answer:

Ber [7]3 years ago

5 0

Answer:

You should have a graph that has the words on the y axis Grade 7 Grade 8 Grade 9 and Grade 10 on each differnt line. Than put the number corosponding to the grade on each line, making the graph rise up and down.

Step-by-step explanation:

Can't make one.

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Solve the algebraic expression below (2/5) (10) + 8

Andrews [41]

Answer: 12.

Step-by-step explanation:

4 0

3 years ago

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

3 years ago

A circle has a Radius of 6meters whats the Circumfrence of the circle?

olya-2409 [2.1K]

6 times 3.1415
u got this

7 0

3 years ago

Read 2 more answers

Negative 5X +3 equals 18

andrey2020 [161]

-5x +3 =18
Subtract 3 from each side
-5x= 15
Divide by -5
x= -3

6 0

4 years ago

Let a= x^2 +4. Rewrite the following equation in terms of a and set it equal to zero.

dusya [7]

Answer:

If:

$a=x^{2}+4$ (1)

And we have to rewrite the following expresion in terms of $a$ :

${(x^{2}+4)}^{2}+32=12x^{2}+48$ (2)

Firstly we have to rearrange the right side of equation (2) in terms of $x^{2}+4$ , factorizing by the common factor:

${(x^{2}+4)}^{2}+32=12(x^{2}+4)$

Then, we can substitute $x^{2}+4$ by $a$ :

$a^{2}+32=12a$

And set it equal to zero:

$a^{2}-12a+32=0$ >>>>This is the resulting equation

Now, each term of an algebraic expresion (like the equation above) is composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).

In this case, the variable is $a$ and the number that multiplies the variable (the coefficient) is $-12$ , whereas the constant (which is the term with no variable) is $32$

6 0

3 years ago

Read 2 more answers