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VMariaS [17]
2 years ago
10

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0
Answer is y = x + 52
you can substitute x with x and substitute y with y
for example:
x = 2 y = 54
54 = 2 + 52
54 = 54
it’s true
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Name a pair of whole number factors whose product is 8
hjlf
"Factors" just means numbers in the context of multiplication - so we just need to name a pair of numbers that, when multiplied, give 8.

Those would be: 1 and 8

2 and 4

so there are two solution to this question: 1 and 8, 2 and 4!

we can also include negative numbers:

-1 and -8
-2 and -4

because a multiplication of two negative numbers gives a positive result!
8 0
3 years ago
Which one is equivalent to the problem ? please help me!!!
lesya692 [45]

Answer:

B

Step-by-step explanation:

This is a power to a power problem. -3 times 2 equals-6. Usually when a number is raised to a negative power, the number is the denominator over 1...with the exponent in the denominator ad well. 5 to the -6 power is 15,605 which is the same as 1/5 to the 6th power....1/15,605

5 0
3 years ago
The student government snack shop sold 32 items this week
Firdavs [7]

Answer:

right the whole question

Step-by-step explanation:

if he sold 32 items this week last week he sold 20

5 0
3 years ago
If Whitney wrote the decimal representations for the first 300 positive integer multiples of 5 and did not write any other numbe
fiasKO [112]

Answer:

201 times

Step-by-step explanation:

Since it's the first 300 positive integer multiples of 5, then the last integer will be: 300 × 5 = 1500

While the first is 5.

The sequence is like this;

5, 10, 15, 20, 25, 30, 35, .. 1500

Since for every 2 integers that are multiples of 5, 1 will include the digit 5, then it means that, number of times the unit place will have 5 is; 300/5 = 150 times

Now, between 5 and 100, the only value that has 5 in it's tense place is 50 & 55.

So for every 100 numbers, we have 2 times to write 5 in the tens place. Thus, for 1500 numbers, we will write 5 in the tens place: 1500/100 × 2 = 30 times

Now, for the hundreds place, from 500 and 600, we have 21 multiples of 5 inclusive of 500 and 600 but since we want the one that has 5 in the hundreds place, then it is 20 as they all start with 5 excluding 600.

Also, from 1000 to 1500, the only number that has 5 in its hundreds place is 1500.

Thus,total times 5 is written in the hundreds place = 21 times

Total number of times 5 is written = 150 + 30 + 21 = 201 times

5 0
3 years ago
Use the Distributive Property to expand 6(-4x + 3y).​
Anna11 [10]

Answer:

-24x + 18y

Step-by-step explanation:

6 x -4x = -24x

6 x 3y = 18y

7 0
3 years ago
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