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KatRina [158]
3 years ago
6

Find the x in the given triangle and at last do the proof...please help​

Mathematics
1 answer:
viva [34]3 years ago
5 0

Answer:

x = 42.67

Step-by-step explanation:

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Christine's grade in the three quarters are 88,91,90. if she targets to have an average grade not less then 92 in the four quart
dezoksy [38]

Total marks C needs to get = 92 x 4 = 368

Least grade (fourth quarter) = 368 - 88 - 91 - 90 = 99

8 0
3 years ago
Can yall pls help me with this, pls try to explain it in steps, ty!
inna [77]

Answer: it MIGHT be c cuz it goes down FASST then slows down a bit on the loop the fast cuz its gong down and then slows a bit

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Bodmass<br><br>-3[2/6+8{-9/3(8-5*3)-6}]​
Vadim26 [7]

9514 1404 393

Answer:

  -361

Step-by-step explanation:

Your calculator can tell you the result. It is -361.

Start with the inner parentheses and work outward. Do multiplication and division in the order shown, left to right, before addition or subtraction.

  -3[2/6+8{-9/3(8-5*3)-6}]​

  = -3[2/6+8{-9/3(8-15)-6}]​

  = -3[2/6+8{-9/3(-7)-6}]​

  = -3[2/6+8{-3(-7)-6}]​

  = -3[2/6+8{21-6}]​

  = -3[2/6+8{15}]

  = -3[1/3+8{15}]

  = -3[1/3+120]

  = -3[361/3]

  = -361

8 0
3 years ago
Find the values of a and b such that x^2-2x+2=(x-a)^2+b
vekshin1

Answer:

a = 1, b = 1

Step-by-step explanation:

Expand the right side and compare the coefficients of like terms on both sides, that is

right side

(x - a)² + b ← expand factor using FOIL

= x² - 2ax + a² + b

Compare to left side x² - 2x + 2

Compare the coefficients of the x- term

- 2a = - 2 ( divide both sides by - 2 )

a = 1

Compare the constant terms

a² + b = 2 ( substitute a = 1 )

1² + b = 2

1 + b = 2 ( subtract 1 from both sides )

b = 1

Thus a = 1, b = 1

6 0
2 years ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
4 years ago
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