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malfutka [58]
1 year ago
13

given y left parenthesis z right parenthesis equals space fraction numerator z squared minus 1 over denominator z left parenthes

is z minus 1 right parenthesis squared end fraction determine the final value
Mathematics
1 answer:
aivan3 [116]1 year ago
5 0

The simplification of the given algebraic expression is;

yz = (z + 1)/z(z - 1)

<h3>How to simplify algebraic expressions?</h3>

We are given y left parenthesis z right parenthesis which is expressed as; yz

Now, we are given the algebraic expression that yz equals space fraction numerator z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction

z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction is expressed as; (z² - 1)/z(z - 1)²

Thus, our main expression is;

yz = (z² - 1)/z(z - 1)²

Factorizing the numerator and denominator gives;

yz = (z + 1)(z - 1)/z(z - 1)(z - 1)

(z - 1) is common to both numerator and denominator and as such, we now have;

yz = (z + 1)/z(z - 1)

Read more about Algebraic Expressions at; brainly.com/question/4344214

#SPJ4

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Step-by-step explanation:

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8 0
3 years ago
Explain how the inverse and the contrapositive of a conditional are alike and how they are different
Alexandra [31]

The converse of the conditional statement is that “If Q then P.” The contrapositive of the conditional statement is “If not Q then not P.” and the inverse of the conditional statement is “If not P then not Q

<h3>How to illustrate the information?</h3>

Conditional: If C, then D. (starting statement)

Inverse: If not C, then not D. (opposite of the conditional)

Contrapositive: If not D, then not C. (reversed opposite of the conditional)

Both the contrapositive and the inverse are opposites of the conditional as both contain not, implying something would not happen under the given circumstances, rather than something would happen under those circumstances.

Learn more about inverse on:

brainly.com/question/3831584

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5 0
2 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
4 years ago
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