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yanalaym [24]
3 years ago
15

Im giving out my points to the one who answers ! :)

Mathematics
2 answers:
romanna [79]3 years ago
5 0

Answer:

hehehehehehehehehehehehehehehehe

Debora [2.8K]3 years ago
3 0

Answer:

thank you so much

Step-by-step explanation:

have a great day

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QUICK HELP!!!<br> How manny differences can you spot? <br> 8<br> 6<br> 7<br> 4<br> 3<br> 5
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Answer:

i can only see 3

Step-by-step explanation:

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Use the quadratic formula to solve for the roots of the following equation.<br> x 2 – 4x + 13 = 0
Artyom0805 [142]
  • Quadratic Formula: x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} , with a = x^2 coefficient, b = x coefficient, and c = constant

With our equation, plug in the values:

x=\frac{4\pm \sqrt{(-4)^2-4*1*13}}{2*1}

Next, solve the exponent and multiplications:

x=\frac{4\pm \sqrt{16-52}}{2}

Next, solve the subtraction:

x=\frac{4\pm \sqrt{-36}}{2}

Next, factor out i (i = √-1):

x=\frac{4\pm \sqrt{36}i}{2}

Next, solve the square root:

x=\frac{4\pm 6i}{2}

Lastly, divide and <u>your answer is:</u>

x=2\pm 3i

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3 years ago
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What is the value of 2 in 0.259
expeople1 [14]
The two is in the tenths place. 
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3 years ago
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A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz
marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean,\mu_xis calculated as:

\mu_x=\mu=204.9, \mu_x=sample \ mean

-The standard deviation,\sigma_x is calculated as:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean,\mu_x is calculated as:

\mu_x=\mu\\\\=75.9

#The sample standard deviation is calculated as follows:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

\mu_x=\mu=135.7

#Sample standard deviation:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0
3 years ago
Solve 2x^2 + 26 = 0 to identify the roots
jok3333 [9.3K]
2x^2=-26
x^2=-13
x=(+/-)sqrt(13)i
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3 years ago
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