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2 years ago

What's the diameter of 76cm circle circumference

Mathematics

1 answer:

pochemuha2 years ago

6 0

Answer:

The circumference of a circle is C = 2πr^2 (2nd power) Radius (r) is the distance from the center of the circle to the outside of it. To find radius divide the diameter (d) by 2. The diameter (d) of a circle is the radius (r) multiplied by 2. To find the diameter (d) you need to do C ÷ π.

For example):

Finding diameter - 76/3.14 = 24.19 (d)

Finding radius - 24.19/2 = 12.095 (r)

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marishachu [46]

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2 years ago

Which equation can be used to find the side lengths if the longest side measures 6.2cm?

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3 years ago

Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to f

Angelina_Jolie [31]

Answer:

$P(z>1.51) =1-P(Z$

And i fwe look into the normalstandar dtable we can find the desired probability:

$P(z>1.51) =1-P(Z$

And then the The area to the right of z = 1.51 is 0.0655

Step-by-step explanation:

For this case we want to find the following probability:

$P(z>1.51)$

And for this case we can use the normal standard distribution and the complement rule and we have this:

$P(z>1.51) =1-P(Z$

And i fwe look into the normalstandar dtable we can find the desired probability:

$P(z>1.51) =1-P(Z$

And then the The area to the right of z = 1.51 is 0.0655

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3 years ago

Find all solutions of the equation: 2cos^2x-cosx=1

Art [367]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166243

——————————

Solve the trigonometric equation:

$\mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}$

Make a substitution:

$\mathsf{cos\,x=t\qquad (-1\le t\le 1)}$

and the equation becomes

$\mathsf{2t^2-t-1=0}$

Rewrite conveniently – t as + t – 2t, and then factor the left-hand side by grouping:

$\mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}$

Factor out 2t + 1:

$\mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}$

Substitute back for t = cos x:

$\begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}$

Therefore,

$\begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}$

where k is an integer.

Solution set:

$\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}$

I hope this helps. =)

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3 years ago

Please help me with math please and explain and thanks

lyudmila [28]

Answer:

Step-by-step explanation:

there are 4 44s in the data set and that is the most repeated so uts the mode

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3 years ago

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