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Alja [10]
2 years ago
5

someone solve all of this will give brainliest to first person that does (only answer circled numbers)

Mathematics
1 answer:
erastovalidia [21]2 years ago
6 0
1. 2, 45. 3, 30. 5, 18. 6, 15
2. Got em all nice work!
3. 2, 26. 4, 13
4. It is prime nice.
5. 15
6. 4
7. Has no factors
8. 14
13. 24
14. 42
15. 12
16. 36
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Please help asap !!!
pashok25 [27]
She would need to but 48 videos to get the cash prize. Hope this helps :)
7 0
2 years ago
Solve for x. <br>0.71= 1/2(9.8) x^2. ​
Fudgin [204]

Answer: 0.38065

in simpler terms x=±  0.145  =±0.38065

Step-by-step explanation: -490x2+71 = 0  

Subtract  71  from both sides of the equation :  

                     -490x2 = -71

Multiply both sides of the equation by (-1) :  490x2 = 71

Divide both sides of the equation by 490:

                    x2 = 71/490 = 0.145

 

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     x  =  ± √ 71/490  

The equation has two real solutions  

These solutions are  x = ±√ 0.145 = ± 0.38065  

5 0
2 years ago
Simplify: (3x^2-5x +9)+(7x^2+8x-5
Ber [7]

Answer:

=10x2+3x+4

Step-by-step explanation:

I hope this helps you

6 0
3 years ago
Read 2 more answers
The pesticide diazinon is in common use to treat infestations of the German cockroach, Blattella germanica. A study investigated
cluponka [151]

Answer:

We conclude that there is no difference in the proportion of cockroaches that died on each surface.

Step-by-step explanation:

We are given that a study investigated the persistence of this pesticide on various types of surfaces.

After 14 days, they randomly assigned 72 cockroaches to two groups of 36, placed one group on each surface, and recorded the number that died within 48 hours. On the glass, 18 cockroaches died, while on plasterboard, 25 died.

<em>Let </em>p_1<em> = proportion of cockroaches that died on glass surface.</em>

<em />p_2<em> = proportion of cockroaches that died on plasterboard surface.</em>

So, Null Hypothesis, H_0 : p_1-p_2 = 0      {means that there is no difference in the proportion of cockroaches that died on each surface}

Alternate Hypothesis, H_A : p_1-p_2\neq 0      {means that there is a significant difference in the proportion of cockroaches that died on each surface}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

                       T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2}  } }  ~ N(0,1)

where, \hat p_1 = sample proportion of cockroaches that died on glass surface = \frac{18}{36} = 0.50

\hat p_2 = sample proportion of cockroaches that died on plasterboard surface = \frac{25}{36} = 0.694

n_1 = sample of cockroaches on glass surface = 36

n_2 = sample of cockroaches on plasterboard surface = 36

So, <u><em>test statistics</em></u>  =  \frac{(0.50-0.694)-(0)}{\sqrt{\frac{0.50(1-0.50)}{36}+\frac{0.694(1-0.694)}{36}  } }

                               =  -1.712

The value of z test statistics is -1.712.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no difference in the proportion of cockroaches that died on each surface.

8 0
3 years ago
Jamie wants to put tiles on the walls and floor of his room (but not on the ceiling). The length of his room is 10 ft, the width
slava [35]

Answer:

Jamie would need 140 tiles.

8 0
3 years ago
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