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Rashid [163]
2 years ago
7

Write the inequality represented by the graph below.

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
6 0

Answer:

y > -x + 3

Step-by-step explanation:

find the slope and y-intercept so you can create a linear equation:

y = mx + b ;   m = slope and  b = y-intercept

slope (m) = (3-0) / (0-3)

m = 3/-3 or -1

we can see the y-intercept by looking at the graph, it is 3

y > -x + 3

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84 of %300. i somehow got 24 but the answer was something like 252, i dont really get how. can you help?
Yuri [45]

Answer:

252

Step-by-step explanation:

Of means multiply

84 % * 300

Change to decimal form

.84 * 300

252

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The answer to the first B one is horizontal translation 1 to the right because the -1 is inside the quantity.
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CAN SOMEONE HELP ME PLEASE ASAP!?
Naddika [18.5K]

Answer:

First option is the correct answer.

14.29\: m^2

Step-by-step explanation:

Area of circular pond

= \pi {r}^{2}  \\  \\  = 3.14 {(7)}^{2}  \\  \\   = 153.86 \:  {ft}^{2}\\\\=\frac{153.86}{(3.2808)^2}\:m^2\\\\=14.29\: m^2

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2 years ago
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In circle O, what is the measure of angle MAJ
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3 years ago
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50 pts!!!! Luciana's laptop has 3,000 pictures. The size of the pictures is skewed to the right, with a mean of 3.7MB and a stan
skelet666 [1.2K]

Answer:

<u></u>

  • <u>Part A: No, you cannot.</u>

<u></u>

  • <u>Part B: 0.4491</u>

Explanation:

<u>Part A:</u>

The mean of samples of symmetrical (bell shaped) distributions follow a normal distribution pattern.

Thus, for symmetrical distributions you can use the z-score tables to make calculations that permit calculate probabilities for particular values.

For <em>skewed </em>distributions, in general, the samples do not follow a normal distribution pattern, except that the samples are large.

Since <em>a sample of 20 pictures</em> is not large enough, the answer to this question is negative: <em>you cannot accurately calculate the probability that the mean picture size is more than 3.8MB for an SRS (skewed right sample) of 20 pictures.</em>

<u>Part B.</u>

For large samples, the<em> Central Limit Theorem</em> will let you work with samples from skewed distributions.

Although the distribution of a population is skewed, the <em>Central Limit Theorem</em> states that  large samples follow a normal distribution shape.

It is accepted that samples of 30 data is large enough to use the <em>Central Limit Theorem.</em>

Hence, you can use the z-core tables for standard normal distributions to calculate the probabilities for a <em>random sample of 60 pictures</em> instead of 20.

The z-score is calculated with the formula:

  • z-score = (value - mean/ (standard deviation).
  • z=(x-\mu )/\sigma

Here, mean = 3.7MB, value = 3.8MB, and standard deviation = 0.78MB.

Thus:

         z=(3.7M-3.8MB)/(0.78MB)=-0.128

Then, you must use the z-score table to find the probability that the z-score is greater than - 0.128.

There are tables that show the cumulative probability in the right end and tables that show the cumulative probability in the left end of a normal standard distribution .

The probability that a z-score is greater than -0.128 is taken directly from a table with the cumulative probability in the left end. It is 0.4491.

4 0
3 years ago
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