Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Answer:
123456678890
Step-by-step explanation:
I think this is the answer
Answer:
come back
Step-by-step explanation:
Answer: 0.15(40) + 0.6(x – 40) = 0.25(x)
Step-by-step explanation:
Hi, to answer this question we have to write an equation with the information given:
Fifteen percent of the pigment in paint color A is black
15% = 15/100 = 0.15 (decimal form)
0.15 A
Sixty percent of the pigment in paint color B is black
0.6 B
An unknown amount of paint color B is mixed with 40 ml of paint color A,
SO:
0.15 (0.40)
0.6 (x-0.40)
x = total amount of paint in the mixture of the two colors
The result is a paint that contains 25% (0.25 in decimal form)black pigment (x)
0.15(40) + 0.6(x – 40) = 0.25(x)
Feel free to ask for more if needed or if you did not understand something.
